Answer:the result is evolution
Explanation: example it can be traced in Mesozoic era by modifications and removing of certain type of reptiles ie dinosaur
Answer:
When water or any other liquid is poured into the communicating tubes shown in Fig. 10.9 it stands at the same level in each tube. This illustrates the popular saying that, “water finds its own level
The alimentary canal and gi tract
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The data suggests that there is no change in height of sheep because of
Hardy Weinberg equillibrium.
Explanation:
Data given:
heights of 200 sheeps remains the same for two years.
reason=?
There is no change in the phenotype of the sheep population during two years as there is no effect of environmental factors, no evolution or genetic drift in the population. Such population happens due to Hardy Weinberg equillibrium.
This principle says that there will be no genetic variation in a population when no evolution causing factors are there. These factors are environmental, mutation, genetic drift, natural selection or gene flow. When no new alleles are added in the population it remains same.
Thus in case of the 200 sheeps it is assumed that they were in Hardy Weinberg equillibrium.
Answer:
(a) Frequency of M = 0.64
Frequency of N = 0.04
Frequency of MN= 0.32
(b) Expected frequencies of M = 0.648
Expected frequencies of MN = 0.304
Expected frequencies of N = 0.048
Explanation:
(a) If random mating takes place in the population, then the expected frequencies are
f(L(M)) = p = 0.8
F(L(N)) = q
q= 1 - p
= 1 - 0.8
= 0.2
Frequency of M = p^2 = ( 0.8)^2 = 0.64
Frequency of N = q^2 = (1-p)^2 = (1 - 0.8)^2 = (0.2)^2 = 0.04
Frequency of MN = 2pq = 2 * 0.8 * 0.2 = 0.32
(b)
F = inbreeding coefficient = 0.05
f(L(M)L(M)) = p^2 + Fpq = (0.8)^2 + 0.05 * 0.8 * 0.2 = 0.648
f(L(M)L(N)) = 2 pq - 2Fpq = 2 * 0.8 * 0.2 - ( 2 * 0.05 * 0.8 * 0.2) = 0.304
f(L(N)L(N)) = q^2 + Fpq = (0.2)^2 + ( 0.05 * 0.8 * 0.2) = 0.048