Answer:

Step-by-step explanation:
<em>Look at the picture.</em>
We have
square with side length a = 9
trapezoid with base lengths b₁ = 9 and b₂ = 6 and the height length h = 6
right triangle with legs lengths l₁ = 3 + 6 = 9 and l₂ = 6
The formula of an area of a square

Substitute:

The formula of an area of a trapezoid:

Substitute:

The formula of an area of a right triangle:

Substitute:

The area of the shape:

Answer:
7.A (5,1)
B(5,7)
8. D (0,6)
Step-by-step explanation:
7. One vertex is at (5,4)
Move 3 units either direction in x
(5-3,4) = (2,4)
(5+3,4) = (8,4)
Or move 3 units in the y direction
(5,4+3) = (5,7)
(5,4-3) = (5,1)
If x is less than 2 or greater than 8 it is too far from the one vertex we are given
If y is less than 1 or greater than 7 it is too far away from the one vertex we are given
C cannot be a vertex since y =9
D is not a vertex since the point is (2,6) and not (2,4) which we know is 3 units away
E is not a vertex since the point is (2,1) and not (2,4) which we know is 3 units away
8. The center is (0,0)
The points have to add to a radius of 6
r^2 = 36
The sum of the x^2 and y^2 = 36
3^2 +0^2 = 9
4^2 +2^2 = 16+4 = 20
5^2 +3^2 = 25+9 = 34
0^2+6^2 =36 yes for D
4^2 +4^2 =16+16 = 32
1^2+5^2 = 26
Answer:
6
Step-by-step explanation:
2*3*6=12
12/2=6
formula= b*h/2
It is the arabic system of numbers. The Roman was the one with Xes and Vs and Is and many other types of markings. Arabs used the 1-9 system, while 0 was taken from the hindu system as it indicates an empty space, so we got the 0-9 system that is commonly used now.

Equation of line passing through given points :
Let's proceed with two point form ~

Assume :




So, the equation of required line is : y = 3 ~