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sukhopar [10]
3 years ago
5

How many solutions does the following equation have ?

Mathematics
2 answers:
fiasKO [112]3 years ago
8 0
The way you find the answer to this is by doing what’s below

-42 - 7 + 10x = -7 + 6x
-49 + 10x = -7 + 6x combine like terms
10x = 42 + 6x add 49 to both sides
4x = 42 subtract 6x from both sides
x = 10.5 divide both sides by 4

hope this helps!!
MatroZZZ [7]3 years ago
3 0
1, the answer is 10.5
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Answer:

<u>Part A: </u>

<u>n = 5q (1st equation)</u>

<u>0.05n + 0.25q = 2 (2nd equation)</u>

<u>Part B:</u>

<u>q = 4 ⇒ n = 5 * 4 = 20</u>

<u>Part C:</u>

<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>

Step-by-step explanation:

Let's recall that a nickel has a value of $ 0.05 and a quarter a value of $ 0.25.

Let n represent the number of nickels and q represent the number of quarters.

Part A:

Write a system of equations to represent the situation.

n = 5q (1st equation)

n * 0.05 + q * 0.25 = 2

0.05n + 0.25q = 2 (2nd equation)

Part B:

Replacing n in the 2nd equation to solve for q:

0.05n + 0.25q = 2

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<u>Part C:</u>

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