Answer:
NO=OP
Step-by-step explanation:
Answer:
12 x^5y^12
Step-by-step explanation:
3x^2y^5 * 4x^3y^7
Multiply the constants
3*4 = 12
Multiply the x terms
x^2 * x^3
We know a^b* a^c = a^(b+c)
x^(2+3) = x^5
Multiply the y terms
y^6 * y^7 = y&(5+7) = y^12
Put them back together
12 x^5y^12
The cage will drop 18.84m for each single rotation of the drum.
It is given that the diameter of the mine winch, d= 6 m.
We can calculate that how far the cage will drop for each single rotation of the drum by using the formula of the circumference.
Circumference, c = 2πr
where,
r = d/2 (radius of the mine winch)
r = 6/2
⇒ r = 3m
Circumference, c = 2πr
⇒ c = 2π×(3)
⇒ c = 6π
⇒ c = 18.84m
Hence, the cage will drop 18.84m for each single rotation of the drum.
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Answer:
An equation
Step-by-step explanation:
this can be solved too
4g + 7e + 4 + 9 + (-4e) + 11 = 5g + 3e + 15
combine like terms
4g + 3e + 24 = 5g + 3e + 15
3e + 24 = g + 3e + 15
24 = g + 15
9 = g
and
0 = e or *no solution* since e cancels itself out.
Answer:
Triangle B
Step-by-step explanation:
Translation is when you slide
