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Alex787 [66]
3 years ago
9

What is the first step to creating a PivotTable?

Computers and Technology
2 answers:
Mrrafil [7]3 years ago
5 0

Answer:    Click anywhere in the dataset.

   Go to Insert –> Tables –> Pivot Table.

   In the Create Pivot Table dialog box, the default options work fine in most of the cases. Here are a couple of things to check in it: ...

   Click OK.

Explanation:

lara31 [8.8K]3 years ago
4 0

Answer:

Click anywhere in the dataset

Go to Insert –> Tables –> Pivot Table.

In the Create Pivot Table dialog box, the default options work fine in most of the cases.

click ok

Explanation:

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Answer:

In order to compose music, EarSketch coders can use samples. Audio samples are located in the sound browser, in the left window, which allows for sound file search, and personal sound file upload. In the left section, users can also show the script browser.

No account is required to create projects or view existing projects. EarSketch comprises different elements: a curriculum, a digital audio workstation (or DAW), a code editor and console, and a sound browser.

Dissolves The dissolve is probably the most used transition in video editing. Also known as a cross-dissolve, this effect layers two clips together so there is a seamless transition from one picture to another. You see it everyday and probably don’t even notice it: and that’s the point.

Explanation:

EarSketch is web-based, which means users can access it with their web-browsers, and with no installation. No account is required to create projects or view existing projects. EarSketch comprises different elements: a curriculum, a digital audio workstation (or DAW), a code editor and console, and a sound browser.

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3 years ago
Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv
elena-s [515]

Answer:

PART ONE

  1. import java.util.Scanner;
  2. public class CountToLimit {
  3.    public static void main(String[] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        int countLimit = 0;
  6.        int printVal = 0;
  7.        // Get user input
  8.        System.out.println("Enter Count Limit");
  9.        countLimit = scnr.nextInt();
  10.        do {
  11.            System.out.print(printVal + " ");
  12.            printVal = printVal + 1;
  13.        } while ( printVal<=countLimit );
  14.        System.out.println("");
  15.        return;
  16.    }
  17. }

PART TWO

  1. import java.util.Scanner;
  2. public class NumberPrompt {
  3.    public static void main (String [] args) {
  4.        Scanner scnr = new Scanner(System.in);
  5.        System.out.print("Your number < 100: ");
  6.       int  userInput = scnr.nextInt();
  7.      do {
  8.           System.out.print("Your number < 100: ");
  9.           userInput = scnr.nextInt();
  10.       }while (userInput>=100);
  11.        System.out.println("Your number < 100 is: " + userInput);
  12.        return;
  13.    }
  14. }

Explanation:

In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14

In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10

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ivann1987 [24]

Answer:

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Explanation:

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QveST [7]

Answer:

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Explanation:

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