All categories

2 years ago

Determine the length of the hypotenuse of a right triangle if the legs have lengths 12 inches and 16 inches?

Mathematics

1 answer:

tiny-mole [99]2 years ago

5 0

Answer:

c = 20 inches

Step-by-step explanation:

To find the sides of a right triangle, you use the Pythagorean Theorem.

a² + b² = c²

You know a and b, and you need to find c, the hypotenuse.

Plug in a and b.

(12)² + (16)² = c²

Simplify by solving the exponents.

144 + 256 = c²

Combine the constants.

400 = c²

Take the square root of both sides.

√400 = √c²

Solve the √

±20 = c

The length cannot be negative, so you can eliminate that as an option.

So, c = 20

You might be interested in

The data set below represents the ages of 11 kids in an after-school program. 10, 11, 8, 7, 6, 10, 7, 10, 9, 9, 12 Which box plo

Andreas93 [3]

Answer:

This is the answer because you need to find mean median mode range, first quertile, third quartile

Whisker plot below

Step-by-step explanation:

Mean (Average) 9

Median 9

Range 6

Mode 10, appeared 3 times

Geometric Mean 8.8206311297046

Largest 12

Smallest 6

Sum 99

Count 11

■ 1st quartile (lower quartile) = 7.5

■ 2st quartile (median) = 9

■ 3st quartile (upper quartile) = 10

8 0

2 years ago

Find the median of the data set. {28,36,78,22,65,38,49,36}

Ostrovityanka [42]

Answer:

37 because 37 was in the middle of all these value when placed dorm smallest ro biggest

4 0

2 years ago

The point-slope form of the equation of a line that passes through points (8,4) and (0, 2) is y-

Oksi-84 [34.3K]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

While the point-slope equation of a line is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

m: It's the slope

$(x_ {0}, y_ {0}):$ It is a point through which the line passes

In this case we have a line through:

(8,4) and (0,2)

Therefore, its slope is:

$m = \frac {2-4} {0-8} = \frac {-2} {- 8} = \frac {1} {4}$

Its point-slope equation is:

$y-4 = \frac {1} {4} (x-8)$

Then, we manipulate the expression to find the equation of the slope-intersection form:

$y-4 = \frac {1} {4} x- \frac {8} {4}\\y-4 = \frac {1} {4} x-2\\y = \frac {1} {4} x-2 + 4\\y = \frac {1} {4} x + 2$

Therefore, the cut-off point with the y-axis is $b = 2$

ANswer:

$y = \frac {1} {4} x + 2$

7 0

2 years ago

All positive real numbers less than or equal ten

Pachacha [2.7K]

Answer:

equal ten

Step-by-step explanation:

hope this helps

7 0

3 years ago

Sec(-45) a. sec 45 b. -sec 125 c. sec 125 d. -sec 45

Pachacha [2.7K]

Step-by-step explanation:

you have forgot to put degree

3 0

2 years ago