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3 years ago

What happens to thermal energy when Kinetic energy is Increased/Decreased?

Physics

1 answer:

Elis [28]3 years ago

3 0

Answer:If kinetic energy increases, so does the thermal energy, and vice versa.

Please brainliest!

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An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time

andrew-mc [135]

Answer:

The object will travel 675 m during that time.

Explanation:

A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the path is a straight line, but the velocity is not necessarily constant because there is an acceleration.

In other words, a body performs a u.a.r.m when its path is a straight line and its acceleration is constant. This implies that the speed increases or decreases uniformly.

In this case, the position is calculated using the expression:

x = xo + vo*t + ½*a*t²

where:

x0 is the initial position.
v0 is the initial velocity.
a is the acceleration.
t is the time interval in which the motion is studied.

In this case:

x0= 0
v0= 0 because the object is initially stationary
a= 6 $\frac{m}{s^{2} }$
t= 15 s

Replacing:

x= 0 + 0*15 s + ½*6 $\frac{m}{s^{2} }$ *(15s)²

Solving:

x=½*6 $\frac{m}{s^{2} }$ *(15s)²

x=½*6 $\frac{m}{s^{2} }$ *225 s²

x= 675 m

<u><em> The object will travel 675 m during that time.</em></u>

5 0

2 years ago

Main ingredient of all cells

Sati [7]

Chloroplast...................

7 0

3 years ago

F = 2.0*10^20 N,

natka813 [3]

$F=\dfrac{Gm_1m_2}{r^2}$

With the given values of $F,G,m_1,r$ , we have

$2.0\times10^{20}\,\mathrm N=\dfrac{\left(6.67\times10^{-11}\,\frac{\mathrm{Nm}^2}{\mathrm{kg}^2}\right)\left(5.98\times10^{24}\,\mathrm{kg}\right)m_2}{\left(3.8\times10^8\,\mathrm m\right)^2}$

Try dealing with the powers of 10 first: On the right, we have

$\dfrac{10^{-11}\times10^{24}}{(10^8)^2}=\dfrac{10^{24-11}}{10^{16}}=10^{-3}$

Meanwhile, the other values on the right reduce to

$\dfrac{6.67\times5.98}{3.8^2}\approx2.76$

Then taking units into account, we end up with the equation

$2.0\times10^{20}\,\mathrm N=\left(2.76\times10^{-3}\,\dfrac{\mathrm N}{\mathrm{kg}}\right)m_2$

Now we solve for $m_2$ :

$m_2=\dfrac{2.0\times10^{20}\,\mathrm N}{2.76\times10^{-3}\,\frac{\mathrm N}{\mathrm{kg}}}\approx0.725\times10^{20-(-3)}\,\mathrm{kg}$

$m_2=7.25\times10^{22}\,\mathrm{kg}$

or, if taking significant digits into account,

$m_2=7.3\times10^{22}\,\mathrm{kg}$

5 0

3 years ago

There is a circuit with 2 resistors in series and a cell of 3.0v.what is the resistance across the first resistor if the current

Marysya12 [62]

Answer:

The resistance of the first resistor is, R₁ = 10 Ω

Explanation:

Given data,

The potential of the cell v = 3 V

The current through the first resistor, I = 0.2 A

The P.D across the first resistor, v₁ = 2.0 V

Let R₁, and R₂ be the resistance of the resistors,

Since the voltage across the series connection is,

v = v₁ + v₂

Substituting the values

3 V = 2 V + v₂

∴ v₂ = 1 V

Hence, the P.D across the second resistor is, v₂ = 1 V

The resistance of the first resistor is,

R₁ = v₁ / I

= 2 V / 0.2 A

= 10 Ω

Hence, the resistance of the first resistor is, R₁ = 10 Ω

6 0

2 years ago

a photon with a wavelength of 2.29x10^-7 meters strikes a mercury atom in the ground state. the photon can be absorbed by the me

Anarel [89]

I just figured this out now.
First you would use the formula
Ephoton= hc/λ and substitute in the value's of plank's constant, the speed of light in a vaccum and the wavelength which will give you the energy in joules. Then you go to the reference table and solve for the energy used between the different levels for Mercury making sure to convert electron volts to jules. In the end the correct answer should be energy level D.

4 0

3 years ago