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olchik [2.2K]
3 years ago
15

Why heat capacity for polymer higher than metal?

Physics
1 answer:
jok3333 [9.3K]3 years ago
4 0
Because polymers are covalently bonded material, and metals are metalicly bonded material. 

Covalent bonds do not let atoms exchange electrons like metalic bonds do.
You might be interested in
When a crown of mass 14.7 kg is submerged in water, an accurate scale reads only 13.4 kg. What material is the crown made of?
Bogdan [553]

Answer:

  ρ = 1.13 10⁴  km/m³

Explanation:

For this exercise we use Newton's equilibrium equation

        B –W + W_scale = 0

Where B is the thrust and W_scale is the balance reading

The push is given by Archimedes' law

        B = ρ_water g V

        B = W- W_scale

        B = m g - m_scale g  

       

Let's calculate

         B = 14.7 9.8 - 13.4 9.8

         B = 12.74 N

         ρ_water g V = 12.74

         V = 12.74 / ρ_water g

         V = 12.74 / 1000 9.8

         V = 0.0013 m³

Let's use density

          ρ = m / V

           

We replace

         ρ = 14.7 / 0.0013

         ρ = 1.13 10⁴  km/m³

3 0
3 years ago
A) How much does an 85g apple weight on the surface of the Earth? (gEarth = 9.8 m/s2)
liq [111]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

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4 0
3 years ago
An object is thrown off a cliff with a horizontal speed of 10 m/sec. After 3 seconds the object hits the ground. Find the height
Degger [83]

Answer:

223

Explanation:

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4 0
2 years ago
Suppose that a particular artillery piece has a range R = 9880 yards . Find its range in miles. Use the facts that 1mile=5280ft
Solnce55 [7]

Answer:

R = 9880 yd * 3 ft/yd / 5280 ft/mi = 5.61 mi

If you do it in steps

R = 9880 yd * 3 ft/yd = 29640 ft

R = 29640 ft / 5280 ft/mi = 5.61 mi

6 0
3 years ago
Calculate the kinetic energy of a 0.032 kg ball as it leaves a hand to be thrown upwards at 6.2 m/s
AnnZ [28]

Answer:

The ball will have a kinetic energy of 0.615 Joules.

Explanation:

Use the kinetic energy formula

E_k = \frac{1}{2}mv^2 = \frac{1}{2}0.032kg\cdot 6.2^2 \frac{m^2}{s^2}= 0.615J

The kinetic energy at the moment of leaving the hand will be 0.615 Joules. (From there on, as it ball is traveling upwards, this energy will be gradually traded off with potential energy until the ball's velocity becomes zero at the apex of the flight)

3 0
3 years ago
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