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Hunter-Best [27]
3 years ago
13

Help asap physics homework, i'll give brainliest

Physics
2 answers:
Georgia [21]3 years ago
7 0

Answer:

a= 0.2 m/s^2\\s  = 20m\\t =  2 s

Explanation:

gievn

two forces are given

f_{1} = 2000 N \\f_{2} = 1800 N\\F_{net} = 2000 -1800  = 200N

A) (a) What is the acceleration of the 1000-kg boat?

f_{net} = ma\\a  = \frac{f_{net}}{m}

     a = \frac{200}{1000}\\a= 0.2 m/s^2

B) If it starts from rest, how far will it move in 10.0 s?

using kinematic equation

s = ut +\frac{1}{2}at^2\\ u = 0  \   m/s\\\\S = \frac{1}{2} at^2 \\s = \frac{1}{2} \times 0.2 \times (10)^2\\s =  10 m

(c) What will its velocity be at the end of this time?

v= u +at \\u = 0 m/s \\v =  0.2\times 10\\v = 2 m/s

Bess [88]3 years ago
5 0

Answer:bippity boppity yee

Explanation:

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The froghopper, Philaenus spumarius, holds the world record for insect jumps. When leaping at an angle of 58.0 above the horizon
kirza4 [7]

Answer:

A) 3.79 m/s  B) 1.33 m

Explanation:

A)

  • Horizontal movement:
  • Once in the air, no forces act on the froghopper, so it keeps moving with the same initial horizontal speed.
  • This horizontal component, is the projection of the velocity vector on the horizontal direction (x-axis):

        v_{ox} = v_{o} *cos (58.0 deg)

  • The horizontal displacement can be simply calculated as follows:

        x = v_{ox} *t

  • Vertical movement:
  • As the vertical and horizontal are independent each other (due to they are perpendicular, so there is no projection of one movement on the other), in the vertical direction, all happens as if would be a body thrown upward with a given initial vertical velocity.
  • This velocity can be found as the projection of the velocity vector on the vertical direction (y-axis):

        v_{oy} = v_{o} *sin (58.0 deg) (1)

  • Once in the air, the gravity will cause that the froghopper be slow down, till it reaches to the maximum height, where it will come momentarily to an stop.
  • In that moment, we can apply the following kinematic equation:

        v_{fy} ^{2} -v_{oy} ^{2} = 2*g*h_{max}

  • where vfy = 0, g = -9.8m/s2, hmax = 52.7 cm= 0.527 m
  • Replacing by the givens, we can solve for voy:

        v_{oy} =\sqrt{2*g*h_{max}} = \sqrt{2*9.8m/s2*0.527m} =3.21 m/s

  • From the equation (1), we can solve for the magnitude of the initial velocity, v₀:

        v_{o} = \frac{v_{oy}}{sin 58.0} =\frac{3.21m/s}{0.848} = 3.79 m/s

B)

  • With the value of the magnitude of the initial velocity, we can find the horizontal component vox, as follows:

        v_{ox} = v_{o} *cos (58.0 deg) =\\  \\ 3.79 m/s * cos (58.0deg) = 2.01 m/s

  • In order to know the horizontal distance travelled, we need to find the time that the insect was in the air.
  • We can use the equation for the vertical displacement, replacing this value by 0, as follows:

       y = 0 = v_{oy} *t -\frac{1}{2} * g *t^{2}

  • Replacing by  the givens, and rearranging terms, we can solve for t:

        t_{air} =\frac{2*v_{oy} }{g} = \frac{2*3.21 m/s}{9.8 m/s} = 0.66 s

  • Finally, we find the horizontal displacement, as follows:

       x_{max}  = v_{ox} *t_{air} = 2.01 m/s * 0.66 s \\ \\ x_{max} = 1.33 m

  • The horizontal distance covered by  the froghopper was 1.33 m.
4 0
3 years ago
Which letter explains why no machine is 100 percent efficient.
kondaur [170]

Answer:

A

Explanation:

Think about rubbing your hands together- the friciton produces heat

4 0
1 year ago
Box A has two moles of gas at a temperature of 400 K. Box B has one mole of gas at a temperature of 800 K. Which of the two gas
mina [271]
B I think if not sorry
8 0
3 years ago
Which of the following would have the greatest force of gravitational attraction?
Mekhanik [1.2K]

Answer:

two 5kg objects 2 meters apart✨

8 0
2 years ago
Tangential velocity 2. Parabolic pathway 3. Projectile 4. Centripetal acceleration 5. Centripetal force a. acceleration towards
Stels [109]

1. Tangential velocity:

<em>e) the instantaneous velocity of a body moving in a circular path.</em>

2. Parabolic pathway

<em>c. a curved path followed by projectiles</em>

3. Projectile

<em>d) an object projected through space, traveling in two dimensions, that accelerates vertically due to gravity.</em>

4. Centripetal acceleration

<em>a) acceleration towards the center caused by the centripetal force</em>

5. Centripetal force

<em>b) a force which keeps a body moving with a uniform speed along a circular path and is directed along the radius towards the center</em>

4 0
2 years ago
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