Question

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Answer 1

Answer:

$a= 0.2 m/s^2\\s = 20m\\t = 2 s$

Explanation:

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two forces are given

$f_{1} = 2000 N \\f_{2} = 1800 N\\F_{net} = 2000 -1800 = 200N$

A) (a) What is the acceleration of the 1000-kg boat?

$f_{net} = ma\\a = \frac{f_{net}}{m}$

     $a = \frac{200}{1000}\\a= 0.2 m/s^2$

B) If it starts from rest, how far will it move in 10.0 s?

using kinematic equation

$s = ut +\frac{1}{2}at^2\\ u = 0 \ m/s\\\\S = \frac{1}{2} at^2 \\s = \frac{1}{2} \times 0.2 \times (10)^2\\s = 10 m$

(c) What will its velocity be at the end of this time?

$v= u +at \\u = 0 m/s \\v = 0.2\times 10\\v = 2 m/s$

Answer 2

Answer:bippity boppity yee

Explanation: