All categories

4 years ago

Help asap physics homework, i'll give brainliest

Physics

2 answers:

Georgia [21]4 years ago

7 0

Answer:

$a= 0.2 m/s^2\\s = 20m\\t = 2 s$

Explanation:

gievn

two forces are given

$f_{1} = 2000 N \\f_{2} = 1800 N\\F_{net} = 2000 -1800 = 200N$

A) (a) What is the acceleration of the 1000-kg boat?

$f_{net} = ma\\a = \frac{f_{net}}{m}$

$a = \frac{200}{1000}\\a= 0.2 m/s^2$

B) If it starts from rest, how far will it move in 10.0 s?

using kinematic equation

$s = ut +\frac{1}{2}at^2\\ u = 0 \ m/s\\\\S = \frac{1}{2} at^2 \\s = \frac{1}{2} \times 0.2 \times (10)^2\\s = 10 m$

(c) What will its velocity be at the end of this time?

$v= u +at \\u = 0 m/s \\v = 0.2\times 10\\v = 2 m/s$

Bess [88]4 years ago

5 0

Answer:bippity boppity yee

Explanation:

You might be interested in

A snail at position 3 cm moves to position 20 cm in 8 seconds.

natulia [17]

Answer: 17cm.

Explanation:

The equation you're using is:

Δd = df - di

Which means the change in position is equal to the final position minus the starting position. In this case that works out to 20cm - 3cm = 17cm. We're only interested in how much the snail moved, not how long it took to move, so even though they give a time it actually doesn't matter for this question.

4 0

3 years ago

A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 2.50 × 1012 m/s2 in a machine. If the proton h

Veronika [31]

Answer:

(A) Speed will be $44.18\times 10^4m/sec$

(b) Change in kinetic energy = $1560\times 10^{-19}$

Explanation:

We have given mass of proton $m=1.67\times 10^{-27}kg$

Acceleration of the proton $a=2.50\times 10^{12}m/sec^2$

Initial velocity u = $1.60\times 10^4$ m/sec

Distance traveled by proton s = 3.90 cm = 0.039 m

(a) From third equation of motion we know that

$v^2=u^2+2as$

$v^2=(1.60\times 10^4)^2+2\times 2.5\times 10^{12}\times 0.039$

$v=44.18\times 10^4m/sec$

(b) Initial kinetic energy $KE_I=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (1.6\times 10^4)^2$

Final kinetic energy $KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2$

So change in kinetic energy $\Delta KE=KE_F-KE_I=\frac{1}{2}\times 1.6\times 10^{-27}\times 10^8\times (44.18^2-1.6^2)=1560\times 10^{-19}J$

6 0

3 years ago

Conduction is the transfer of heat in: 1 gases 2 liquids 3 solids

kykrilka [37]

Answer:

Conduction heat transfer is the transfer of heat by means of molecular excitement within a material without bulk motion of the matter.

Explanation:

Conduction heat transfer in gases and liquids is due to the collisions and diffusion of the molecules during heir random motion.

4 0

2 years ago

In some circumstances,science will answer questions about what is good and what is evil true or false?

bagirrra123 [75]

Your answer is false since science is a subject not a religion

4 0

3 years ago

A truck is traveling at 2.0 m/s. It slows to a stop at a constant rate over 3.00 s. How far does the car travel during those 3.0

earnstyle [38]

Answer:

During those 3.00 seconds before stopping, the car travels a distance of 6 m.

Explanation:

The simple rule of three is a tool that is used to quickly solve problems, where three pieces of information must be known, and one of them operates as an unknown to be known.

Two magnitudes are directly proportional if one magnitude increases the other also does it, and if the magnitude decreases the other in the same way.

Being a, b and c known data and x the unknown, the value that we want to know, the rule of three when the magnitudes are directly proportional is applied as follows:

a ⇒ b

c ⇒ x

So: $x=\frac{c*b}{a}$

In this case, knowing that a truck travels at 2 m/s, the rule of three applies as follows: if in 1 second the truck travels 2 m, in 3 seconds how much distance does it travel?

$distance=\frac{3 s*2 m}{1 s}$

distance= 6 m

During those 3.00 seconds before stopping, the car travels a distance of 6 m.

8 0

3 years ago