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BartSMP [9]
4 years ago
6

The position coordinate of a particle which is confined to move along a straight line is given by s =2t3−24t+6, where s is measu

red in meters from a convenient origin and t is in seconds. Determine (a) the time required for the particle to reach a velocity of 72 m/s from its initial condition at t = 0, (b) the acceleration of the particle when v = 30 m/s, and (c) the net displacement of the particle during the interval t = 1 s to t = 4 s.
Physics
1 answer:
Gre4nikov [31]4 years ago
7 0

Answer:

a) the answer is t=4 seconds

b) acceleration is zero

c) displacement= 142 m

Explanation:

Given the position of the particle

s=2t^3-24t+6

a) the time required when velocity v=72 m/s

v=72=\frac{ds}{st}=6t^2-24

now we solve for time t

6t^2=72+24=96\\\\\implies t^2=\frac{96}{6}\\\therefore t=4 s

b) acceleration when v=30 m/s

acceleration is the time derivative of velocity i.e

a=\frac{dv}{dt}=\frac{d}{dt}(30)=0

c) the net displacement of the particle during the interval t = 1 s to t = 4 s is

s_4-s_1=2t^3-24+6|_{t=4}-2t^3-24+6|_{t=1}\\s_4-s_1=126-(-16)=142 m

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3 years ago
A train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds. What is
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Answer:

1900 metres

Explanation:

Given that a train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds.

The parameters to be considered are:

Speed = 30 m/s

Time = 30 seconds

Speed = distance/time

Substitute the parameters into the formula

30 = distance / 30

Cross multiply

Distance = 30 × 30

Distance = 900 m

Since the train started from a position of 1000 m , the final position will be:

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6 0
3 years ago
A car is driving 55 miles per hour east. The car changes direction to head north but still travels at 55 miles per hour. Which i
bezimeni [28]

Answer:

Just as distance and displacement have distinctly different meanings (despite their similarities), so do speed and velocity. Speed is a scalar quantity that refers to "how fast an object is moving." Speed can be thought of as the rate at which an object covers distance. A fast-moving object has a high speed and covers a relatively large distance in a short amount of time. Contrast this to a slow-moving object that has a low speed; it covers a relatively small amount of distance in the same amount of time. An object with no movement at all has a zero speed.

7 0
3 years ago
Read 2 more answers
In lab you find that a 1-kg rock suspended above water weighs 10 N. When the rock is suspended beneath the surface of the water,
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Answer:

a. 2N

b. 12N

c. 20N

Explanation:

Dtaa given,

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weight of rock in water =8N

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The buoyant force is calculated as 10N-8N=2N

b. The scale reading will be the sum of the buoyant force and the weight of the container

scale reading =10N+2N=12N

c. When the rock rest at the bottom of the container, the weight of the rock(10N) is acting downward and the weight of the container also is acting downward. Hence the sum of the two weight gives the reading on the scale

scale reading=10N+10N=20N

4 0
3 years ago
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