1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BartSMP [9]
3 years ago
6

The position coordinate of a particle which is confined to move along a straight line is given by s =2t3−24t+6, where s is measu

red in meters from a convenient origin and t is in seconds. Determine (a) the time required for the particle to reach a velocity of 72 m/s from its initial condition at t = 0, (b) the acceleration of the particle when v = 30 m/s, and (c) the net displacement of the particle during the interval t = 1 s to t = 4 s.
Physics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

a) the answer is t=4 seconds

b) acceleration is zero

c) displacement= 142 m

Explanation:

Given the position of the particle

s=2t^3-24t+6

a) the time required when velocity v=72 m/s

v=72=\frac{ds}{st}=6t^2-24

now we solve for time t

6t^2=72+24=96\\\\\implies t^2=\frac{96}{6}\\\therefore t=4 s

b) acceleration when v=30 m/s

acceleration is the time derivative of velocity i.e

a=\frac{dv}{dt}=\frac{d}{dt}(30)=0

c) the net displacement of the particle during the interval t = 1 s to t = 4 s is

s_4-s_1=2t^3-24+6|_{t=4}-2t^3-24+6|_{t=1}\\s_4-s_1=126-(-16)=142 m

You might be interested in
There are many risks associated with nuclear power. Which is NOT a risk associated with nuclear power?
andrew11 [14]
1. I think is letter b.
2. I thinks it's letter c.
6 0
3 years ago
Read 2 more answers
A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source
ololo11 [35]

Answer:

0.027 J

Explanation:

The formula of the potential energy in electrostatic (U) is

U = q \times E \times d

The values given in the question are

Charge : q = 4.5 \times 10^{-5} C

Electric Field strength : E = 2.0 \times 10^{4} N/C

Distance : d  is 0.030 m

Insert in the formula , will give us

U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m

Further solving it

U = 0.027 J

Which is the required answer.

Thanks

5 0
3 years ago
An organization's _______ expresses the need the firm will fill, the operations of the business, its components and functions, a
sergiy2304 [10]

Answer:

Business Model

Explanation:

A business model is basically a plan of how a business will make a profit. It indicates what type of services or goods they will deliver, who they will provided services to, and the expenses to expect.

A good business model can be used to attract investors, motivate staff and management and recruit potential talent into the business.

7 0
3 years ago
You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi
Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0
3 years ago
A reservoir located in the mountain 250 m above sea level flows through a pipe to a hydroelectric plant in a town at sea level.
Pavlova-9 [17]

Answer:

     v₂ = 70 m / s

Explanation:

For this exercise let's use Bernoulli's equation

where subscript 1 is for the top of the mountain and subscript 2 is for Tuesday's level

 

          P₁ + ½ ρ v₁² + ρ g y₁ = P₂ +1/2 ρ v₂² + ρ g y₂

indicate that the pressure in the two points is the same, y₁ = 250 m, y₂ = 0 m, the water in the upper part, because it is a reservoir, is very large for which the velocity is very small, we will approximate it to 0 (v₁ = 0), we substitute

         ρ g y₁ = ½ ρ v₂²

         v₂ = \sqrt {2g \ y_1}

let's calculate

         v₂ = √( 2 9.8 250)

         v₂ = 70 m / s

6 0
3 years ago
Other questions:
  • What is the s. i unit of current​
    15·2 answers
  • an archer stands 40.0m from the target. if the arrow is shot horizontally with a velocity of 90.0 m/s, how far above the bull's
    13·1 answer
  • If the vector represents velocity this number represents the speed
    13·1 answer
  • What is the kinetic energy of a 1.0-kg billard ball that moves at 5.0 m/s?
    9·1 answer
  • How many elements are there in total in the periodic table?
    12·2 answers
  • Hey can anyone help me with my physics exam​
    11·2 answers
  • What is another word that can be used to describe the position of the<br> object?
    5·1 answer
  • Explain how to convert a galvanometer to an ammeter
    12·1 answer
  • What is the Net Force of the applied forces? *
    6·1 answer
  • If you are good at activities that require agility, what are you able to do well?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!