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Degger [83]
3 years ago
9

What force is represented by the vector​

Physics
2 answers:
vlada-n [284]3 years ago
8 0
Answer/explanation: A force vector is a representation of a force that has both magnitude and direction.
fiasKO [112]3 years ago
4 0

Answer:

i think that the correct answer would be normal force

Explanation:

so sorry if this is wrong

plz mark brainlest

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givi [52]

I would say the answer is B

Hope it helps!

5 0
3 years ago
In which situation is maximum work considered to be done by a force
Katena32 [7]

Answer:

  • Work done is maximum when the movement of object is in line and direction of force.  

OR

  • Work done is maximum, when displacement takes place along the direction of force.
  • Work done is given by the equation

                                W = F.S

                            <em>     W  = F. S cos Θ</em>

<em>When cos Θ = 0° ; cos 0 = 1</em>

3 0
3 years ago
Read 2 more answers
Two point charges are 10.0cm apart and have charges of 2.0uC and -2.0uC, respectively. What is the magnitude of the electric fie
elena-14-01-66 [18.8K]
The electric field generated by a point charge is given by:
E= k_e \frac{Q}{r^2}
where
k_e = 8.99 \cdot 10^9 Nm^2 C^{-2} is the Coulomb's constant
Q is the charge
r is the distance from the charge

We want to know the net electric field at the midpoint between the two charges, so at a distance of r=5.0 cm=0.05 m from each of them. 

Let's calculate first the electric field generated by the positive charge at that point:
E_1=k_e  \frac{Q_1}{r^2}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(2.0 \cdot 10^{-6} C)}{(0.05 m)^2} =+7.19 \cdot 10^6 N/C
where the positive sign means its direction is away from the charge.

while the electric field generated by the negative charge is:
E_2=k_e \frac{Q_1}{r^2}=(8.99 \cdot 10^9 Nm^2C^{-2}) \frac{(-2.0 \cdot 10^{-6} C)}{(0.05 m)^2} =-7.19 \cdot 10^6 N/C
where the negative sign means its direction is toward the charge.

If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:
E_{tot} =E_1 + E_2 = 7.19 \cdot 10^6 N/C+7.19 \cdot 10^6 N/C=1.44 \cdot 10^7 N/C
3 0
3 years ago
A satellite is in orbit 36000km above the surface of the earth. Its angular velocity is 7.27*10^-5 rad/s. What is the velocity o
bagirrra123 [75]

Answer:

v = 3.08 km/s

Explanation:

Given that,

The angular velocity of the satellite = \omega=7.27\times 10^{-5} rad/s

A satellite is in orbit 36000km above the surface of the earth.

The radius of the earth is 6400 km

Let v is the velocity of the satellite. It can be calculated as :

v=r\omega\\\\v=(36000\times 10^3+6400\times 10^3)\times 7.27\times 10^{-5}\\\\v=3082.48\ m/s\\\\v=3.08\ km/s

So, the velocity of the satellite is 3.08 km/s.

6 0
3 years ago
True or false? If the speed of an object doubles, its kinetic energy will also double.
Anastasy [175]

Answer:

False

Explanation:

It's kinetic energy would change to four times the amount.

4 0
3 years ago
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