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Answer:
the probability of no defects in 10 feet of steel = 0.1353
Step-by-step explanation:
GIven that:
A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.
Let consider β to be the average value for defecting
So;
β = 2
Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.
Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2
i.e

the probability mass function can be represented as follows:

where;
y = 0,1,2,3 ...
Hence, the probability of no defects in 10 feet of steel
y = 0


P(y =0) = 0.1353
It is expected to depreciate from 4400 to 800 in 6 years. The depreciation per year is the ratio
depreciation per year = (total depreciation) / (number of years)
The total depreciation is the change in value, so the depreciation per year is
(4400 - 800)/6 = 600
Karen expects the vehicle to depreciate by 600 each year.
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Answer:
i think it is A, C, OR B, **For the first equation**
Step-by-step explanation:
SRRY IF WRONG!