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3 years ago

Andre correctly solved an equation using the steps shown:

Mathematics

1 answer:

Pepsi [2]3 years ago

3 0

Answer:

This equation has zero solutions.

Step-by-step explanation:

This equation has zero solutions because 2 is not equal to zero.

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Use the reference angles to find the exact value of the expression cot -11 pi/6. Do not use a calculator

laiz [17]

Answer:

$\sqrt{3}$

Step-by-step explanation:

cot(-11pi/6)=cot(-pi-5pi/6)= -cot(5pi/6)=cot(pi/6)= $\sqrt{3}$ ≈1.73

7 0

3 years ago

A book normally costs 21.50. today it was on sale for 15.05. how much is the discount?

arsen [322]

Answer:

$6.45

Step-by-step explanation:

$21.50-$15.05=$6.45

6 0

3 years ago

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What is the best way to study and get good grades

sp2606 [1]

Answer: The best way to study is by getting flashcards or something to help you review stuff and the best way to get good grades is by studying, doing your homework, doing your classwork, extra credit any work can help you get good grades AND STUDY!

Step-by-step explanation:

8 0

3 years ago

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M (3, –6) is rotated 90° counterclockwise. (x, y) → (–y, x) 1. Switch the x- and y-coordinates: (6, –3) 2. Multiply the new x-co

GalinKa [24]

Answer:

The answer is below

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation is rotation, reflection, translation and dilation.

If a point (x, y) is rotated 90° counterclockwise, its new coordinate is (–y, x).

Give point M (3, –6) is rotated 90° counterclockwise:

Step 1: Interchange the x- and y-coordinates to get (-6, 3)

Step 2: Multiply the new x-coordinate by –1 to get (-6(–1), 3)

Step 3: Simplify to get (6, 3)

Therefore she made an error in step 1

3 0

2 years ago

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If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),

Anna007 [38]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0

3 years ago

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