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zhannawk [14.2K]
3 years ago
11

Simplify the expression. 5 square root of 224x^11y^8

Mathematics
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

The first is correct!

Step-by-step explanation:

224=7*2^5.

X^11=X*x^10

Y^8=y^3*y^5

5th sqrt(7*2^5)=2* 5th sqrt(7)

5th sqrt(x*x^10)=x^2 * 5th sqrt(x)

5th sqrt(y^3 * y^5)= y* 5th sqrt(y^3)

So the 5th sqrt(224x^11y^8) is

2x^2 *y * 5th sqrt(7xy^3)

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Annette [7]

Answer: y= -4x-2

Step-by-step explanation:

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3 years ago
64 A fisherman traveled in a boat from point N upstream. After having traveled 6 km, he stopped rowing and 2 hour 40 min after f
Leviafan [203]
Let c represent the speed of the current.

time = distance / speed

total time = time going upriver + time going downriver
2 2/3 = 6/(9 -c) + 6/c
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(8/3)c^2 -24c +54 = 0
c = (24 ± √((-24)^2 -4(8/3)(54)))/(2*8/3)
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4 0
3 years ago
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Helen [10]

Answer:△JKL∼△STU

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Step-by-step explanation:

7 0
3 years ago
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WRITE AN EQUATION TO DESCRIBE THE RELATIONSHIP BETWEEN J AND Mj | 4 | 12 | 20m | 3 | 9 | 15
galina1969 [7]

First, we can use the points (4,3) and (20,15) to find the slope of the line:

\begin{gathered} s=\frac{m_2─m_1}{j_2─j_1}=\frac{15─3}{20─4}=\frac{12}{16}=\frac{3}{4} \\ s=\frac{3}{4} \end{gathered}

Now we can find the relation function using the point (4,3) and the slope s=3/4

\begin{gathered} m─m_1=s(j─j_1) \\ \Rightarrow m─3=\frac{3}{4}(j─4)=\frac{3}{4}j─(\frac{12}{4})=\frac{3}{4}j─3 \\ m=\frac{3}{4}j \end{gathered}

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4 0
1 year ago
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Licemer1 [7]

Answer:

(0,-1)

Step-by-step explanation:

x point is 6, and the translation is x - 6

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Coordinates are (0,-1)

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