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3 years ago

Help please!!!!! Geometry

Mathematics

1 answer:

Fofino [41]3 years ago

7 0

Answer:

<B = 47

Step-by-step explanation:

(5x+7) = (3x+23)

5x+7 = 3x+23

2x+7 = 23

2x = 16

2x/2 = 16/2

x = 8

<B = 3x+23

<B = 3(8)+23

<B = 24 + 23

<B = 47

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A ball is thrown vertically upward from the ground with an initial velocity of 111 ft/sec. Use the quadratic function h(t) = −16

ddd [48]

Answer:

t=3.5 seconds

Step-by-step explanation:

Given

h(t) = −16t^2 + 111t + 0

h'(t)= -32t + 111

Maximum height occurs when h(t) = 0 and the ball begins to fall

h(t)= -32t + 111=0

-32t + 111=0

-32t=-111

Divide both sides by -32

t=3.46872

Approximately, t=3.5 seconds

Recall,

Maximum height occurs when h(t) = 0

h(t)= -32t + 111=0

= -32(3.46872)+111

= -110.99904+111

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DaniilM [7]

Answer:

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Step-by-step explanation:

Given

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3 years ago

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prisoha [69]

Answer:

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Step-by-step explanation:

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sweet-ann [11.9K]

Step-by-step explanation:

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Step-by-step explanation:

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