Question

A ray of light is incident from air on the surface of a block of clear ice (nice=1.31) at an angle of 45.0° with the normal. Part of the light is reflected and part is refracted. Find the angle between the reflected and refracted light.

Answer 1

Answer: θ = 102.3°

Explanation:

The reflected light will depart at 45.0° from the normal

Snell's law for the refracted light

1.00sin45 = 1.31sinθ

θ = arcsin(sin45.0/1.31) = 32.66840... ≈32.7°

The angle between these is 180 - 45 - 32.7 =  102.3°