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3 years ago

What is the vector sum of (7,5) and (13,-5)?

Physics

1 answer:

-BARSIC- [3]3 years ago

8 0

To add or subtract two vectors, just add or subtract the corresponding components. This is:

(7, 5) + (13, -5) = (7+13 , 5-5) = (20, 0)

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65 Points! 9 Questions!

alekssr [168]

Answer:

energy : the ability to cause change

work : is force x distance or when an object moves a distance due to a specific force (measured in units of newtons-meters)

potential energy : is stored energy

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4 years ago

____________ are manufactured by the brain to help relieve pain. Ventricles Epinephrines Endorphins Phalanges

VMariaS [17]

It's Endorphins. That's a pain killer produced by the brain.

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3 years ago

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4 years ago

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What is the total energy q released in a single fusion reaction event for the equation given in the problem introduction? use c2

kkurt [141]

Answer:

$4.3\cdot 10^{-12} J$

Explanation:

The fusion reaction in this problem is

$4^1_1H \rightarrow ^4_2He +2e^+$

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$\Delta E = c^2 \Delta m$

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\Delta m$ is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products

For this fusion reaction we have:

$m(^1_1H)=1.007825u$ is the mass of one nucleus of hydrogen

$m(^4_2 He)=4.002603u$ is the mass of one nucleus of helium

So the mass defect is:

$\Delta m =4m(^1_1 H)-m(^4_2 He)=4(1.007825u)-4.002603u=0.028697u$

The conversion factor between atomic mass units and kilograms is

$1u=1.66054\cdot 10^{-27}kg$

So the mass defect is

$\Delta m =(0.028697)(1.66054\cdot 10^{-27})=4.765\cdot 10^{-29}kg$

And so, the energy released is:

$\Delta E=(3.0\cdot 10^8)^2(4.765\cdot 10^{-29})=4.3\cdot 10^{-12} J$

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3 years ago

If this did not happen, what would be the approximate force on an eardrum of area 0.22 cm2 if a change in altitude of 1500 m tak

jeyben [28]

Complete Question

When you ascend or descend a great deal when driving in a car yours ears "pop," which means that the pressure behind the eardrum is being equalized to that outside. If this did not happen, what would be the approximate force on an eardrum of area .50 cm2 if a change in altitude of 950 m takes place?

Answer:

The value is $F = 0.60 \ N$