Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by

where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:

and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:

So you’d put 1.5 by the 6 so it’d be 6(1.5) to the power of 2. then you’d do 1.5*1.5=2.25*6=13.5
Step-by-step explanation:
secants originating from the same point have the same relative length relationship :
outside part × sum of outside and inside parts
is the same for every secant from the same point.
so,
5×(7+5) = 6×(2x-8+6) = 12x - 12
60 = 12x - 12
12x = 72
x = 6
WV = 2x - 8 = 2×6 - 8 = 12 - 8 = 4
so, B is correct.
Answer:
x = 0
y = -4
negative 4 cuz the line goes down, meaning it's negative