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Slav-nsk [51]
4 years ago
8

Round down this calculation to Ofe ucci piacer ). Order: Uniphyl (theophylline) 5 mg/kg po loading dose stat. The strength of th

e Uniphyl is 400 mg per tablet. How many tablets of this bronchodi- lator would you administer to a patient who weighs 76 kg?
Mathematics
1 answer:
Marta_Voda [28]4 years ago
7 0

Answer:

1 tablet

Step-by-step explanation:

Data provided in the question:

The dose of the Uniphyl = 5 mg/kg

Strength of the Uniphyl = 400 mg per tablet

Weight of the patient = 76 kg

Now,

The recommended dose for the patient            

= Dose of the Uniphyl × weight of the patient

= 5 mg/kg × 76 kg

= 380 mg

Therefore,

The number of tablets to be administered to the patient

= \frac{\textup{Recommended dose for the patient}}{\textup{Strength of the Uniphyl}}

= \frac{\textup{380}}{\textup{400}}

= 0.95 ≈ 1 tablet

Hence,

The number of tablets to be administered to the patient is 1

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Can Somebody Please Explain How To Do It? THANKS
sergejj [24]

Hello from MrBillDoesMath!

Answer:

9


Discussion:

Solution 1:

Distance between two points (x1, y1), (x2,y2) is given by the formula

sqrt(  (x1-x2)^2 + (y1-y2)^2).  In our case this becomes

sqrt( (0-0)^2 +  (12 -3)^2 ) =

sqrt( 9^2) =

9.


Solution 2:

Note points D and E both have x = 0 so segment DE is a vertical segment. The length is simply the difference of the y coordinates: 12- 3 = 9 as before.


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MrB

6 0
3 years ago
Here we will study the function f (x) = e ^ x sin (x), where x ∈ [0, 2π]. a) Determine where the function is decreasing and incr
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fff

f(x) = e^x sin (x)

To find increasing and decreasing intervals we take derivative

f'(x) = e^xsin(x)+e^x(cosx)= e^x(sinx+cosx)

Now we set the derivative =0  and solve for x

e^x(sinx+cosx)=0

sinx + cosx =0

divide whole equation by cos x

\frac{sinx}{cosx} + \frac{cosx}{cosx} =0

tanx +1 =0

tanx = 1

x=\frac{3\pi }{4} and  x=\frac{7\pi}{4}

Now we pick a number between 0 to  \frac{3\pi }{4}

Lets pick  \frac{\pi }{2}

Plug it into the derivative

f'(x) =e^{\frac{\pi }{2}}(sin(\frac{\pi}{2})+cos(\frac{\pi }{2}))

= 4.810 is positive

So the graph of f(x) is increasing on the interval [0, x=\frac{3\pi }{4})

Now we pick a number between   \frac{7\pi}{4} to 2pi

Lets pick  \frac{11\pi}{6}

Plug it into the derivative

f'(x) =e^{\frac{11\pi}{6}}(sin(\frac{11\pi}{6})+cos(\frac{11\pi }{6}))

= 116 is positive

So the graph of f(x) is increasing on the interval (\frac{7\pi }{4}, 2\pi)

Increasing interval is (0,\frac{3\pi }{4}) U (\frac{7\pi }{4}, 2\pi)

Decreasing interval is (\frac{3\pi}{4}, \frac{7\pi}{4})

(b)

The graph of f(x) increases and reaches a local maximum at x=\frac{3\pi}{4}

The graph of f(x) decreases and reaches a local minimum at x=\frac{7\pi}{4}

(c)

f(0) = 0

f(2\pi)=0

f(\frac{3\pi }{4})=7.46

f(\frac{7\pi}{4})=-172.64

Here global maximum at x=\frac{3\pi}{4}

Here global minimum at x=\frac{7\pi}{4}


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4 years ago
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The longer one is 2.16.

             



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4 years ago
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John and Jake are facing each other from a distance. Iniko turns counter-clockwise 30° and starts walking. Vaughan turns clockwi
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The angle between paths simply refers to sum of the angles of both paths should the line of the paths be extended indefinitely to the point where they both meet.

The problem above is envision as indicated in the attached image. Recall that they were both facing each other - thus creating an imaginary straight line.

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7 0
3 years ago
The measures of the angles of a triangle are shown in the figure. solve for x
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Answer:

10

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