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Slav-nsk [51]
3 years ago
8

Round down this calculation to Ofe ucci piacer ). Order: Uniphyl (theophylline) 5 mg/kg po loading dose stat. The strength of th

e Uniphyl is 400 mg per tablet. How many tablets of this bronchodi- lator would you administer to a patient who weighs 76 kg?
Mathematics
1 answer:
Marta_Voda [28]3 years ago
7 0

Answer:

1 tablet

Step-by-step explanation:

Data provided in the question:

The dose of the Uniphyl = 5 mg/kg

Strength of the Uniphyl = 400 mg per tablet

Weight of the patient = 76 kg

Now,

The recommended dose for the patient            

= Dose of the Uniphyl × weight of the patient

= 5 mg/kg × 76 kg

= 380 mg

Therefore,

The number of tablets to be administered to the patient

= \frac{\textup{Recommended dose for the patient}}{\textup{Strength of the Uniphyl}}

= \frac{\textup{380}}{\textup{400}}

= 0.95 ≈ 1 tablet

Hence,

The number of tablets to be administered to the patient is 1

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Given the midpoint and one endpoint of a line segment, find the other endpoint.
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\bf -------------------------------\\\\ \cfrac{x+\frac{5}{8}}{2}=-\cfrac{7}{6}\implies  x+\cfrac{5}{8}=-\cfrac{14}{6}\implies x=-\cfrac{14}{6}-\cfrac{5}{8} \\\\\\ x=\cfrac{-14(4)-5(3)}{24}\implies x=\cfrac{-56-15}{24}\implies \boxed{x=-\cfrac{71}{24}}\\\\ -------------------------------\\\\ \cfrac{y+\frac{27}{8}}{2}=-\cfrac{10}{3}\implies y+\cfrac{27}{8}=-\cfrac{20}{3}\implies y=-\cfrac{20}{3}-\cfrac{27}{8} \\\\\\ y=\cfrac{-20(8)-27(3)}{24}\implies y=\cfrac{-160-81}{24}\implies \boxed{y=-\cfrac{241}{24}}

3 0
3 years ago
Please help with these problems <br> thank you so much!<br><br> 9. 10. 11. 12. 13. 14.
Ket [755]
9) 216 in
10) 12 yd
11) 3.75 ft
12) 30 yd
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4 0
4 years ago
Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un
Snowcat [4.5K]

Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

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v_1\ =\ 20i\ +\ 25j

  • and the velocity of second car

v_2\ =\ 30i

=> speed of first car,

u_1\ =\ \sqrt{(20)^2+(25)^2}

      =\ \sqrt{400+625}

       =\ \sqrt{1025}

       = 32.01 units

and speed of second car,

u_2\ =\ \sqrt{(30)^2+(0)^2}

        = 30 units

u_2\ -\ u_1\ =\ 32.01\ -30

               = 2.01 units

Hence, 2nd car is running faster than the first car by 2.01 units.

8 0
3 years ago
A. the object’s motion does not change.
sukhopar [10]
Answer:
D. the object accelerates

Explanation:
Based on Newton's first law: "An object will maintain its state of rest or motion unless an external force acts on it"
An unbalanced forced means that there is a net force acting on the object. This will lead the object to either speed up, slow down, come to rest or change its direction.
This means that the net force caused by the unbalanced force will lead the object to accelerate.

Hope this helps :)
5 0
4 years ago
Mieko said that the difference between the longest rose and the shortest rose is 1 inch. Is she correct?
erastova [34]

Answer:

Mieko is correct

Step-by-step explanation:

Given

See attachment for complete question

Required

The length difference

Lengths with dot(s) means, there is at least 1 rose flower of that length.

So, from the attachment, we have:

Longest = 14.0

Shortest = 13.0

The difference (d) is:

d = Longest - Shortest

This gives:

d = 14.0 - 13.0

d = 1\ in

<em>Hence, Mieko is correct</em>

3 0
3 years ago
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