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tangare [24]
3 years ago
8

6th grade math please help me in all 10 questions.​

Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer:

d

Step-by-step explanation:

bagirrra123 [75]3 years ago
5 0

Answer:

D the answer is D

Step-by-step explanation:

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Mr. Dean has an even number of cats and an odd number of dogs. Show how many dogs and cats he might have
kirill115 [55]
1 dog and 2 cats..................................
6 0
4 years ago
A group of friends were working on a student film that had a budget of $600. They
Snezhnost [94]

Answer:55%

Step-by-step explanation:

330/600=0.55

55%

6 0
3 years ago
Find the equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3).
Romashka-Z-Leto [24]

The equation of the line that is parallel to the line x + 5y = 10 and passes through the point (1, 3) in slope intercept form is y = \frac{-1}{5}x + \frac{16}{5}

<h3><u>Solution:</u></h3>

Given that a line is parallel to line x + 5y = 10 and passes through the point (1, 3)

We have to find the equation of line

<em><u>The slope intercept form is given as:</u></em>

y = mx + c  -------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

<em><u>Let us first find the slope of line</u></em>

Given equation of line is x + 5y = 10

5y = -x + 10\\\\y = \frac{-1}{5}x + \frac{10}{5}\\\\y = \frac{-1}{5}x + 2

On comparing the above equation of line with slope intercept form,

m = \frac{-1}{5}

We know that slopes of parallel lines are equal

So the slope of line parallel to given line is also m = \frac{-1}{5}

<em><u>Let us find the equation of line with slope m = -1/5 and passes through the point (1, 3)</u></em>

\text {substitute } m=\frac{-1}{5} \text { and }(x, y)=(1,3) \text { in eqn } 1

3 = \frac{-1}{5} \times 1 + c\\\\15 = -1 + 5c\\\\16 = 5c\\\\c = \frac{16}{5}

<em><u>Thus the required equation is:</u></em>

\text {substitute } m=\frac{-1}{5} \text { and } c=\frac{16}{5} \text { in eqn } 1

y = \frac{-1}{5}x + \frac{16}{5}

Thus the required equation of line is found

3 0
3 years ago
The lengths of text messages are normally distributed with a population standard deviation of 6 characters and an unknown popula
ryzh [129]

Answer:

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

Step-by-step explanation:

We have the standard deviation for the population, so we can use the normal distribution. If we had the standard deviation for the sample, we would have to use the t-distribution.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.5 = 0.9, so z = 1.282

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.282*\frac{6}{\sqrt{21}} = 1.68

The lower end of the interval is the sample mean subtracted by M. So it is 30 - 1.68 = 28.32 characters.

The upper end of the interval is the sample mean added to M. So it is 30 + 1.68 = 31.68 characters.

The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.

6 0
3 years ago
PQRS is a rectangle and OS = 16. Find the blanks below:
GalinKa [24]

Answer: 48

Step-by-step explanation:

4 0
3 years ago
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