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kogti [31]
3 years ago
9

Define Potential Difference ​

Physics
1 answer:
GarryVolchara [31]3 years ago
3 0

Answer:

the difference of electrical potential between two points.

Explanation:

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Select the correct answer.
Murrr4er [49]

Answer:

I will choose the answer A

3 0
3 years ago
How and why will my weight change if i took a trip to the moon
MatroZZZ [7]

weight less on moon than on earth.

high on lift off - G force

low in orbit.

zero at a point between earth and moon

7 0
3 years ago
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The outer planets are similar to the planet Earth; they just happen to be farther away from the Sun.
Harrizon [31]

Answer:

False

Explanation:

The inner planets are called terrestrial planets due to the surfaces are solid (similar to Earth)-made up of heavy metals, either have no moons or few moons.

The outer planets are called Jovian planets or gas giants because they are encased in gas.  They all have rings with plenty of moons.

5 0
3 years ago
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An electromagnet is created using a battery, an insulated copper wire and an iron nail. The wire is wrapped around the nail 20 t
Molodets [167]
I think adding more loops would strengthen it
4 0
3 years ago
Earth's neighboring galaxy, the Andromeda Galaxy, is a distance of 2.54×10^7 light-years from Earth. If the lifetime of a human
kupik [55]

Answer:

0.9999986*c

Explanation:

The ship would travel 2.54*10^7 light years, which means that at a speed close to the speed of light the trip would take 2.54*10^7 years from the point of view of an observer on Earth. However from the point of view of a passenger of that ship it will take only 70 years if the speed is close enough to the speed of light.

\Delta t = \Delta t' * \sqrt{1 - (\frac{v}{c})^2}

Where

Δt is the travel time as seen by a passenger

Δt' is the travel time as seen by someone on Earth

v is the speed of the ship

c is the speed of light in vacuum

We can replace the fraction v/c with x

\Delta t = \Delta t' * \sqrt{1 - x^2}

\sqrt{1 - x^2} = \frac{\Delta t}{\Delta t'}

1 - x^2 = (\frac{\Delta t}{\Delta t'})^2

x^2 = 1 - (\frac{\Delta t}{\Delta t'})^2

x = \sqrt{1 - (\frac{\Delta t}{\Delta t'})^2}

x = \sqrt{1 - (\frac{70}{2.54*10^7})^2} = 0.9999986

It would need to travel at 0.9999986*c

5 0
3 years ago
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