Answer:
V = 4.826m/s, 716N
Explanation:
At the lowest swinging point, the net force acting on the child is equal to the centripetal force and it could be represented as
F = mv^2/r
2T-mg =mv^2/r
r(2T-mg) = mv^2
Divide both sides by m
r(2T-mg)/m = mv^2/m
r(2T/m-g) = v^2
V= √ r(2T/m-g)
Where v is the velocity
r is the length of the chain
m is the mass of the child in kg
T is the tension in Newton
g is the acceleration due to gravity
Given that g = 9.8m/s^2
T = 358N
m = 41.0kg
r = 3.04m
Substituting the values into the formula
V = √ 3.04( 2*358/41 -9.89
V = √ 3.04 ( 716/41 - 9.8 )
V = √3.04 ( 17.463-9.8 )
V = √3.04( 7.6634)
V = √23.2967
V = 4.826m/s
For the second part which is the tension in the two chains
N - m*g = m*(v^2 / r)
N - (41)*(9.81) = (41)*(4.826^2 / 3.04)
N - 402.21 = 41×7.66
N - 402.21 = 314.112
N = 402.21 + 314.112
N = 716.332 newton
Approximately = 716N
Or alternatively, since there are two chains holding the swing, of which each chain is acted upon by a 358N tension. Hence = 2T
2*358 = 716N
Answer:
Explanation:
From the 1st Law of linear motion which states that when a body goes into motion, it will continue doing so until it is stopped by force. So the body of the rider keeps moving until it is been stopped and the stopping could be as a result of an impact of any part of the body which includes the head it an object. Also the 3rd Law of Motion will also be applicable because for every action, there will be equal and opposite reaction. The magnitude of the impact will be as a result of the force with which the crash took place as well.
When crashes take place the rider does not always experience a head impact square on with a solid obstruction. During a bike crash, your head comes in contact with the ground. The ground exerts a force that causes your head to stop moving. Often impact will be at an angle and may not be head first. It may be your shoulder will hit first, then your side, and then your head will receive a glancing blow against the ground as you slide.
The ground exerts so much force that it can stop our forward motion within seconds. Without your motorcycle helmet, your head experiences a huge amount of concentrated force during a crash.
Answer:
1.429*10^-5 m
Explanation:
From the question, we are given that
Diameter of the cable, d = 3 cm = 0.03 m
Force on the cable, F = 2 kN
Young Modulus, Y = 2*10^11 Pa
Area of the cable = πd²/4 = (3.142 * 0.03²) / 4 = 0.0028 / 4 = 0.0007 m²
The fractional length = Δl/l
Δl/l = F/AY
Δl/l = 2000 / 0.0007 * 2*10^11
Δl/l = 2000 / 1.4*10^8
Δl/l = 1.429*10^-5 m
Therefore, the fractional length is 1.429*10^-5 m long
Answer:
The net force acting on the object is doubled while the mass of the object is held constant. What will be the new acceleration? An object has an acceleration of 12.0 m/s^2. The net force acting on the object is halved (decreased to one half its original value) while the mass of the object is held constant.
