In 1967, John Wheeler invented the name "black hole" for the first time. However, there is no unified naming system for black holes.
Answer:
Current = 0.063 Amperes
Explanation:
Let the three resistors be R1, R2, and R3 respectively.
Given the following data;
R1 = 25.0Ω,
R2 = 30.0Ω
R3 = 40.0Ω
Voltage = 6 Volts
First of all, we would determine the equivalent or total resistance;
Total resistance (in series) = R1 + R2 + R3
Total resistance = 25.0Ω + 30.0Ω + 40.0Ω
Total resistance = 95 Ω
Next, we find the current flowing through the circuit;
Voltage = current * resistance
Substituting into the formula, we have;
6 = current * 95
Current = 6/95
Current = 0.063 Amperes
Answer: 2561.7 pounds
Explanation:
If we assume the total weight of an airplane (in pounds units) as a <u>linear function</u> of the amount of fuel in its tank (in gallons) and we make a Weight vs amount of fuel graph, which resulting slope is 5.7, we can use the slope equation of the line:
(1)
Where:
is the slope of the line
is the airplane weight with 51 gallons of fuel in its tank (assuming we chose the Y axis for the airplane weight in the graph)
is the fuel in airplane's tank for a total weigth of 2390.7 pounds (assuming we chose the X axis for the a,ount of fuel in the tank in the graph)
This means we already have one point of the graph, which coordinate is:
Rewritting (1):
(2)
As Y is a function of X:
(3)
Substituting the known values:
(4)
(5)
(6)
Now, evaluating this function when X=81 (talking about the 81 gallons of fuel in the tank):
(7)
(8) This means the weight of the plane when it has 81 gallons of fuel in its tank is 2561.7 pounds.
Answer:
3.98V
Explanation:
Given
Pontential difference V as 3v
Energy delivered is 30%,
Recall that Enery E=1/2cv^2 from this E=V^2(since Current C is not provided we can assume a value 2)
So E=V^2
E=3^2=9
At full charge E=9,30%of 9,0.3*9=2.7 energy in capacitor is 9-2.7=6.3
But E=V^2
✓E=V
✓6.3=3.98V
