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Alex_Xolod [135]
3 years ago
12

Which players are usually the tallest on their team, and stay close to the basket so they can shoot and rebound the ball?

Physics
1 answer:
alexdok [17]3 years ago
7 0

Answer:

Center

Explanation:

The center is the tallest player on each team, playing near the basket. On offense, the center tries to score on close shots and rebound. But on defense, the center tries to block opponents' shots and rebound their misses.

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Two particles move along an x axis. The position of particle 1 is given by x ! 6.00t 2 # 3.00t # 2.00 (in meters and seconds); t
s344n2d4d5 [400]

Answer:

15.6m/s

Explanation:

V1=\frac{dx}{dt}=\frac{d}{dt}(6t^{2}+3t+2) because the derivate of the position is the velocity

V1=12t+3

V2=20+\int\limits^_ {} \,-8t because the integral of the acceleration is the velocity

V2=20-4t^{2}

V1=V2 to see when the velocities of particles match

12t+3=20-4t^2

4t^2+12t-17=0 we resolve this with \frac{-b+-(\sqrt{b^{2} -4ac} )}{2a}

and we take the positif root

t=1.05 sec

if we evaluate the velocity (V1 or V2) the result is 15.6m/s

7 0
3 years ago
Which of the following parts of John Dayton’s atomic theory
horrorfan [7]

Answer:

Atoms (small elements) ARE REAL!!!

Explanation:

mind blowing...

8 0
3 years ago
ANSWER One end of a string is attached to an object of mass M, and the other end of the string is secured so that the object is
qaws [65]

Answer:

Explanation:

It is a case of oscillation by simple pendulum . Expression for simple pendulum is given as follows

T = 2\pi\sqrt{\frac{l}{g} }

where T is time period , l is length of pendulum and g is acceleration due to gravity .

\frac{1}{f} =2\pi\sqrt{\frac{l}{g} }  , f is frequency of oscillation

For the given case

\frac{1}{f_o} =2\pi\sqrt{\frac{l}{g} }

subsequently length becomes half so

\frac{1}{f} =2\pi\sqrt{\frac{l}{2g} }

dividing

\frac{f}{f_o} = \sqrt{\frac{2}{1} }

f = \sqrt{2} f_o

frequency of oscillation becomes √2 times.

4 0
3 years ago
The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is
kodGreya [7K]

Answer:

\frac{T_t}{T_c} = 1.32

Explanation:

The torque applied on an object can be calculated by the following formula:

T = Fr

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

T_c = Fr_c\\

For truck wheel:

T_t = Fr_t

Dividing both:

\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}

for the same force applied on both wheels:

\frac{T_t}{T_c} = \frac{r_t}{r_c} \\

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\

\frac{T_t}{T_c} = 1.32

8 0
3 years ago
To raise an armpit upward the muscle on one side of it contracts what happens Elton the muscle on the opposite side of the arm
Ghella [55]

Answer:

It relaxes

Explanation:

I took the test I hope it helps

7 0
3 years ago
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