Atoms of the same element having equal numbers of protons, but different numbers of neutrons is called isotope.
<span>a. In the process of induction, metal objects are positive because electrons are pushed out of the object to the earth. The mass of the object decreases by an amount equal to the mass of the electrons leaving the metal object.</span>
b. <span>During the induction process, electrons are drawn from the earth to the object, so that the metal object becomes negative. <span>The mass of the object increases by an amount equal to the mass of "excess" electrons dragged onto the object.</span></span>
Say we have a cylinder
that has a height of dx, we see that the cylinder has a volume of: <span>
<span>Vcylinder = πr^2*h = π(5)^2(dx) = 25π dx
Then, the weight of oil in this cylinder is:
Fcylinder = 50 * Vcylinder = (50)(25π dx) = 1250π dx.
Then, since the oil x feet from the top of the tank needs to
travel x feet to get the top, we have:
Wcylinder = Force x Distance = (1250π dx)(x) = 1250π x dx.
<span>Integrating from x1 to x2 ft gives the total work to be: (x1
= distance from top liquid level to ground level; x2 = distance from bottom
liquid level to ground level)</span>
<span>W = ∫ 1250π x dx
<span>W = 1250π ∫ x dx
W = 625π * (x2 – x1)</span></span></span></span>
<span>x2 = 14 ft + 15 ft = 29 ft</span>
x1 = 14 ft + 1 ft = 15
ft
<span>
W = 625π * (29^2 - 15^2)
<span>W = 385,000π ft-lbs
= 1,209,513.17 ft-lbs</span></span>
Answer:
a) 1955.6 J
b) 1955.6 J
c) 2607 N
d) 110373 J
Explanation:
a)
b) Work done on bullet should be increase in KE = 1955.6 J
c) Work done = Force \times displacement = KE of bullet
d) Work done to stop
initial velocity = 0 = v₍i₎
final velocity = ? = v₍f₎
t = 12 sec
Acceleration = 4m/s²
First we have to find the distance d, for this we use the
formula,
D = v₍i₎t + 1/2at²
D = 0(12) + ½ (4)(12)²
Distance = d = 288 m
Now to find the Vf use the formula,
V₍f₎² = v₍i₎² + 2ad
V₍f₎² = (0)2 + 2(4)(288)
V₍f₎² = 2304
V₍f₎ = 48 m/s
so the velocity at the end of 12 sec is 48 m/s