The strength of the electric field on the point charge at this distance will be 4000 V/m.
<h3>What is the strength of the electric field?</h3>
The strength of the electric field is the ratio of electric force per unit charge.
The given data in the problem is;
Qis the unit charge = 4.0 × 10⁻⁶ C
E is the strength of the electric field
R is the distance from point charge = 3 m
The strength of the electric field is;
Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.
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Answer:
The electrical field in the region between the plates is 10,000 V/m.
Explanation:
Given;
potential difference between the two parallel plates, V = 100 V
distance between the two parallel plates, d = 1 cm = 0.01 m
The electrical field in the region between the plates is given as;
E = V / d
where;
E is the electrical field in the region between the plates
E = (100) / (0.01)
E = 10,000 V/m
Therefore, the electrical field in the region between the plates is 10,000 V/m.
<span>The nickel has a mass of approximately 0.005kg</span>
Answer:
b. 0.75 mm
Explanation:
The distance between antinodes d is half the wavelength 
. We can obtain the wavelength with the formula 
, where f is the frequency given (
) and v is the speed of sound in body tissues (v=1540m/s), so putting all together we have:
which is very close to the 0.75mm option.
