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swat32
3 years ago
10

How much force is required (in Newton’s) to accelerate a 4-kg skateboard, along with its 46-kg rider, at 3m/s2?

Physics
1 answer:
Soloha48 [4]3 years ago
5 0

Answer:150N

Explanation:

Total mass=mass of skate board + mass of rider

Total mass(m)=46kg + 4kg

Total mass(m)=50kg

Acceleration(a)=3m/s^2

Force(f)=mass x acceleration

Force=50 x 3

Force=150N

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A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the
svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength  is given by

           \lambda = \dfrac{2L}{n}

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the frequency expression is given by

            f = n\dfrac{v}{2L}

now, wavelength calculation

      n = 1

           \lambda_1 = \dfrac{2\times 2}{1}

                    λ₁ = 4 m

      n = 2

           \lambda_2 = \dfrac{2\times 2}{2}

                   λ₂ = 2 m

      n =3

           \lambda_3 = \dfrac{2\times 2}{3}

                    λ₃ = 1.333 m

now, frequency calculation

      n = 1

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            f = n\dfrac{v}{2L}

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            f = n\dfrac{v}{2L}

            f_3 =3\times \dfrac{50}{2\times 2}

                    f₃ = 37.5 Hz

8 0
3 years ago
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