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Rainbow [258]
3 years ago
11

When examining evidence, why might investigators want to be more careful examining chemical properties than physical properties.

Physics
1 answer:
tatuchka [14]3 years ago
8 0

Answer:

Please find the answers in the explanation

Explanation:

In examination of any scientific observation, some experiments may be needed to be carried out.

When examining evidence, the investigators might want to be more careful examining chemical properties than physical properties because anything that involve chemical reaction are irreversible. While physical one can be reversible.

Also, reaction can easily take place when examining the chemical properties of some substances.

It is seldom for reaction to take place with physical one.

there can be some complications and danger with chemical properties but less complication and danger with physical one.

Therefore, the investigators will want to be more careful when examining evidence on chemical properties than physical properties due to the given reasons above.

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An object has a kinetic energy of 14 j and a mass of 17 kg how fast is the object moving
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  • KE=14J
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\\ \sf\Rrightarrow kE=\dfrac{1}{2}mv^2

\\ \sf\Rrightarrow 14=\dfrac{1}{2}17v^2

\\ \sf\Rrightarrow 17v^2=28

\\ \sf\Rrightarrow v^2=28/17

\\ \sf\Rrightarrow v^2=1.64

\\ \sf\Rrightarrow v\approx 0.13m/s

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Consult Multiple-Concept Example 5 for insight into solving this problem. A skier slides horizontally along the snow for a dista
Gennadij [26K]

Answer:

The speed with which the skier was going is approximately 2.9906 m/s

Explanation:

The given parameters are;

The distance the skier slides before coming to rest, s = 12.4 m

The coefficient of friction between the skier and the snow, \mu _k = 0.0368

Therefore, for conservation of energy, we have;

Initial kinetic energy = Work done by the kinetic friction force

Initial kinetic energy = 1/2·m·v²

The work done by the kinetic friction force = \mu _k×m×g×s

Where;

m = The mass of the skier

v = The speed with which the skier was going

g = The acceleration due to gravity = 9.8 m/s²

s = The distance the skier slides before coming to rest = 12.4 m

\mu _k = The kinematic friction = 0.0368

Therefore, for conservation of energy, we have;

1/2·m·v² = \mu _k×m×g×s

1/2·v² = \mu _k×g×s

v² = 2×\mu _k×g×s  = 2 × 0.0368 × 9.8 × 12.4 = 8.943872

v = √(8.943872) ≈ 2.99063070271 ≈ 2.9906 m/s

The speed with which the skier was going = v ≈ 2.9906 m/s.

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3 years ago
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