(a) Energy is conserved at every point in the block's motion, so the potential energy P stored in the first spring at its maximum compression is the same as is stored in the second spring.
The total work performed on the block by the first spring is
W = -1/2 (110 N/m) (0.21 m²) = -2.4255 J
The work performed by the second spring is the same, so
W = -1/2 (240 N/m) x²
Solve for x :
x² = -2W/(240 N/m) = 0.0202125 m²
x ≈ 0.14 m = 14 cm
(b) By the work-energy theorem, the total work performed by either spring on the block as the spring is compressed is equal to the change in the block's kinetic energy. The restoring force of the spring is the only force involved. At maximum compression, the block has zero velocity, while its kinetic energy and hence speed is maximum just as it comes into contact with either spring.
W = 0 - K
W = -1/2 (0.10 kg) v²
v² = -2W/(0.10 kg) = 48.51 m²/s²
v ≈ 7.0 m/s
Answer: Current = 2 A
Explanation:
Given that an electrical power plant generates electricity with a
current I = 50 A
Potential difference V = 20 000 V
The resistance R will be achieved by Ohms law formula which state that
V = IR
But the power generated will be the product of potential difference and the current
Power P = IV
P = 50 × 20000
P = 1, 000000 W
When the transformer steps up the potential difference to 500 000 V before it is transmitted
Power is always constant.
Using the formula for power again with
V = 500000
1000000 = 500000× I
Make I the subject of formula
Current I = 1000000/500000
Current I = 2 A
Amphere. I hope this helps!
Answer:
No.
Explanation:
The spare tire is also moving at the speed of the jeep. When it separates from the jeep, both will be moving at the same horizontal speed, only that the spare tire will also fall at the same time. This if we neglect air friction, that could be a problem since it could cancel the horizontal velocity of the spare tire, although the jeep is blocking most of the air for the spare tire to feel any significant effect in such a short time.
<span>Mass doesn't change when the temperature
of the ball changes.
(Unless, of course, it gets so hot that it melts,
and part of it falls off
and rolls under the table.)</span>
