X is 7 more than y
x>y then
difference betwen squares is 161 so
x=7+y
and
x²-y²=161
so
x=7+y
sub that for x in other equation
(7+y)²-y²=161
y²+14y+49-y²=161
14y+49=161
minus 49 both sides
14y=112
divide both sides by 14
y=8
sub back
x=7+y
x=7+8
x=15
the numbers are 15 and 8
Now this may or may not be work I’m 99.9 percent sure it’s right but if not sorry
8/14 in lowest terms is 4/7
X-axis = A (-7,-3) B (-7,-10) C (-1,-3) first they changed to the x-axis which is this. Just so you know on the x-axis the x-axis stay and the y-axis changed which is this.
When they reflect again on the y-axis the verter of A' is
A' (7, 3) = answer
On the y-axis the y- axis doesnt change but the x-axis changed.
Hope this help!
Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.