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Olin [163]
3 years ago
14

A snail can crawl at a rate of 6 cm in 0.75 minutes. Which represents the constant rate of change of the snail's crawl?

Mathematics
1 answer:
andrew11 [14]3 years ago
7 0

Answer:

<h3>0.00133m/s</h3>

Step-by-step explanation:

Given

distance crawled by the snail = 6cm = 0.06m

Time taken = 0.75minutes = 0.75*60

Time taken = 45secs

Required

constant rate of change of the snail's crawl (speed)

Speed of the snail = distance/time;

Speed of the snail = 0.06/45

Speed of the snail = 0.00133m/s

Hence the constant rate of change of the snail's crawl in m/s is 0.00133m/s

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steposvetlana [31]

Answer:

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Step-by-step explanation:

Given:

One end point A=  (2,5)

Mid point M = (4,0)

To Find:

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Solution:

According to midpoint formula, if (x1, y1) and (x2, y2) are two ends of a line then it’s midpoint is given by :  

M(x,y)= \frac{x1+ x2}{2} ,\frac{y1+ y2}{2}

Using the above formula

4=\frac{2+x_2}{2}..................................(1)

0=\frac{5+y_2}{2}..................................(2)

Solving equation(1)

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x_2=8-2

x_2=6

Solving equation(2)

0\times 2=\frac{5+y_2}{2}

0=5+y_2

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Thus x_2=6 and  y_2 =-5

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Step-by-step explanation:

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