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Free_Kalibri [48]
3 years ago
13

Write the equilibrium constant expression for the reaction below.

Chemistry
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

Explanation:

The equilibrium constant indicates the % of the yield reaction and can shows where the reaction is going to be equilibrated.

It works with molar concentrations on the equilibrium and it does not consider the solids compounds

Kc also can be modified by the time of the reaction.

This reaction is:

CS₂ (g) + 4 H₂O(g) ⇌ CH₄ (g) + 2H₂S (g)

Kc = [H₂S]² . [CH₄] / [ H₂O]⁴ . [CS₂]

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What is the mass of 22.4 L of H2 at STP?
Vanyuwa [196]

A. 1.01 is the right answer

Since

The formula is Pv= nRT

P=1 atm

V= 22.4 L

N= x

r= 0.0821

t = 273 k (bc it’s standard temperature)

So (1)(22.4)=(x)(0.0821)(273)

X= 1.001

7 0
3 years ago
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A certain half-reaction has a standard reduction potential -1.33V . An engineer proposes using this half-reaction at the anode o
Paha777 [63]

Answer:

a. -0.63 V

b. No

Explanation:

Step 1: Given data

  • Standard reduction potential of the anode (E°red): -1.33 V
  • Minimum standard cell potential (E°cell): 0.70 V

Step 2: Calculate the required standard reduction potential of the cathode

The galvanic cell must provide at least 0.70V of electrical power, that is:

E°cell > 0.70 V    [1]

We can calculate the standard reduction potential of the cathode (E°cat) using the following expression.

E°cell = E°cat - E°an   [2]

If we combine [1] and [2], we get,

E°cat - E°an > 0.70 V

E°cat > 0.70 V + E°an

E°cat > 0.70 V + (-1.33 V)

E°cat > -0.63 V

The minimum E°cat is -0.63 V and there is no maximum E°cat.

3 0
3 years ago
500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.
jarptica [38.1K]

The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated HCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted HCl solution

We are given:

M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL

Putting values in above equation, we get:

0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M

Hence, the concentration of diluted solution is 0.16 M

5 0
3 years ago
Name the compound mg3cl2 is it magnesium chloride?
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No 
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The method I use to name ionic compounds is 'swap and drop' 

Mg oxidation number is +2 and Cl oxidation number is -1
Mg^2+         Cl^-1  
'swap'
Mg^1           Cl^2 
'drop' 
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What is the formula for P &amp; Cl​
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Answer:

I belive it is PCl3

5 0
2 years ago
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