Answer: a) 0.0144mol/L
b) 
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as 
The equation for the ionization of the
is given as:
We are given:
Solubility of
= 
Molar Solubility of
= 
1 mole of
gives 1 mole of
and 2 moles of
ions
Solubility product of
= ![[Pb^{2+}][Cl^-]^2](https://tex.z-dn.net/?f=%5BPb%5E%7B2%2B%7D%5D%5BCl%5E-%5D%5E2)
![K_{sp}=[0.0144][2\times 0.0144]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5B0.0144%5D%5B2%5Ctimes%200.0144%5D%5E2)

Thus the solubility product constant is 
Answer:
1.67×10^-1
Explanation:
Use the formula n=m/R.M.M
Find the R.M.M. Formula of the compound is AgNO3.
So Ag mass is 108, N mass is 14, and O mass is 16.
So 108+14+(16×3)=170.
Than use formula n=28.39/170 giving 0.167. In scientific notation 1.67×10^-1.
I think