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tangare [24]
3 years ago
6

Photo attached please help ​

Mathematics
1 answer:
Katarina [22]3 years ago
3 0

Answer:

A

Step-by-step explanation:

Multiply:

(\frac{5}{5+\sqrt{10x} } )(\frac{5+\sqrt{10x} }{5+\sqrt{10x} } )

Simplify:

\frac{5(5-\sqrt{10x}) }{(5+\sqrt{10x})(5-\sqrt{10x} ) }

Factor:

\frac{5(5-\sqrt{10x}) }{25-10x}

Reduce:

\frac{5(5-\sqrt{10x}) }{5(5-2x)}

Solution:

\frac{5-\sqrt{10x} }{5-2x}

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A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,
katovenus [111]

Answer:

z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620  

p_v =2*P(Z>1.620)=0.105  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation  

X_{1}=45 represent the number of correct answers for university degree holders

X_{2}=57 represent the number of correct answers for university non-degree holders  

n_{1}=373 sample 1 selected

n_{2}=639 sample 2 selected

p_{1}=\frac{45}{373}=0.121 represent the proportion of correct answers for university degree holders  

p_{2}=\frac{57}{639}=0.0892 represent the proportion of correct answers for university non-degree holders  

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.  

Since is a one side test the p value would be:  

p_v =2*P(Z>1.620)=0.105  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0
3 years ago
PLEASE HELP???!!!!!
Likurg_2 [28]
We'll use the Pythagorean Theorem
130^2 = side^2 +50^2
side ^ 2 = 16,900 -2,500
side ^ 2 = 14,400
side = square root (14,400)
side = 120 feet



4 0
3 years ago
Read 2 more answers
Find the equation of a line parallel to y=6 that passes through (4,3)
ozzi

Answer: 4

Step-by-step explanation:

8 0
3 years ago
Please help me with this Math question...
kati45 [8]

Answer:

A) length = 9cm, width = 4 cm

Step-by-step explanation:

The key word "times" refers to multiplication, so if you're trying to find dimensions at 1/4 times its original size, you need to multiply the original dimensions by 1/4.

l = 36

new l = 36 (1/4)

          = 36/4

          = 9 cm

w = 16

new w = 16 (1/4)

            = 16/4

            = 4 cm

5 0
3 years ago
Find the average rate of change for the function f(x) =x^2 -6x+2 on the closed side interval (-5,2)
s344n2d4d5 [400]

Answer:

- 9

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [a, b ] = [ - 5, 2 ], thus

f(b) = f(2) = 2² - 6(2) + 2 = 4 - 12 + 2 = - 6

f(a) = f(- 5) = (- 5)² - 6(- 5) + 2 = 25 + 30 + 2 = 57 , thus

average rate of change = \frac{-6-57}{2-(-5)} = \frac{-63}{7} = - 9

6 0
3 years ago
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