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MariettaO [177]
4 years ago
14

Write the ratios for sin A and cos B. The triangle is not drawn to scale.

Mathematics
1 answer:
babymother [125]4 years ago
4 0
By definition we have:
 sineA = (C.O) / (h)
 cosA = (C.A) / (h)
 Where,
 C.O: opposite leg
 C.A: adjacent leg
  h: hypotenuse
 Substituting values:
 sinA = (48) / (50)
 cosA = (14) / (50)
 Answer:
 sineA = (48) / (50)
 cosA = (14) / (50) 
 Option 2
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