Question

Write the ratios for sin A and cos B. The triangle is not drawn to scale.

Answer 1

By definition we have:
 sineA = (C.O) / (h)
 cosA = (C.A) / (h)
 Where,
 C.O: opposite leg
 C.A: adjacent leg
  h: hypotenuse
 Substituting values:
 sinA = (48) / (50)
 cosA = (14) / (50)
 Answer:
 sineA = (48) / (50)
 cosA = (14) / (50) 
 Option 2