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Katen [24]
2 years ago
10

What is the solution to the following equation?

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
8 0

Answer:

7 7/9

Step-by-step explanation:

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What is the explicit formula for the sequence below?<br><br> 4, -12, 36, -108 ...
Temka [501]

Answer:

This is a geometry sequence (I.e each term is found by multiplying the same value to the previous term).

T1 = 4

T2 = -12 = T1 X (-3) = 4 X (-3)

T3 = 36 = T2 X (-3) = 4 X (-3)^2

T4 = 108 = T3 X (-3) = 4 X (-3)^3

The general (explicit) formula for the n-th term of this sequence is:

S(n) = 4 X (-3)^(n-1)

4 0
3 years ago
Hey anyone know the answer?
aivan3 [116]

Answer:

DC

Step-by-step explanation:

ABCDE ≅ GHJDF

GH ≈ AB

DJ ≈ DC

4 0
3 years ago
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What is the volume of the rectangular prism.
Pie

Answer:

C: 200

Step-by-step explanation:

Just multiply 12.5 x 8 x 2 to get the answer.

3 0
2 years ago
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6(14+x)=108, umm please help
My name is Ann [436]

Answer:

X = 4

I hope this helps

if you could, feel free to mark me Brainliest it would be much appreciated :D

4 0
3 years ago
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
3 years ago
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