Interesting problem.
First - let's figure cost of each uniform at purchase.
3,000/40 = $75 each
When some uniforms were returned at $40 - there was a difference of $35 in what they paid and what they rec'd in return. ($75 - 35 = $40)
Answer:
Derivative: P’(x) = 200 - 2x
If P’(x) = 0 , x = 100
Therefore P’ is positive and P increases until x = 100
So the maximum units to maximize profits is 100 units
And for 100 units the profit in dollar is:
20000 - 10000 = 10000
10000 dollars
10% of 59 = 5.9
59 - 5.9 = 53.1
answer: sale price is $53.1
Answer:
midpoint formula: (x₁ + x₂)/2, (y₁ + y₂)/2
distance: √[(x₂ - x₁)² + (y₂ - y₁)²]
Step-by-step explanation:
What points are you trying to calculate the distance and the midpoint for?
The answer is 6, this is because the first step is you put the numbers in order then you find the mode by seeing what number is the most
