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N76 [4]
2 years ago
12

What does it mean to raise a power to another power? PLS HELPPP

Mathematics
1 answer:
iris [78.8K]2 years ago
6 0

Answer:

it means To raise a power to a power means to raise one exponent to another. Whether the exponents are real, imaginary, monomials or polynomials, to simplify these problems, all you have to do is multiply the exponents together. Hope this helps

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Factor completely 4p2 - 25q2 =
mel-nik [20]
Answer: 2(4p - 25q)


Explanation: 4p*2 = 8p - 25q*2 = 8p - 50q = 2(4p - 25q)
6 0
3 years ago
Express as a trinomial.<br> (x-3)(3x+6)
Strike441 [17]

Answer:

3x^2 - 3x + 18

Step-by-step explanation:

x*3x=3x^2

(x*6)+(-3*3x)=-3x

-3*6=-18

4 0
2 years ago
How is completing the square beneficial?
Lelechka [254]
If it is, then you can solve the equation by taking the square root of both sides of the equation. ... Next, if the coefficient of the squared term is 1 and the coefficient of the linear (middle) term is even, completing the square is a good method to use. Finally, the quadratic formula will work on any quadratic equation
8 0
2 years ago
What is the slope of the line that
lutik1710 [3]

Answer:

2

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

m = ( 8-2)/(3-0)

   = 6/3

   = 2

7 0
3 years ago
Read 2 more answers
A pebble is dropped into a deep well and 3s later the sound of a splash is heard as the pebble reaches the bottom of the well. T
ankoles [38]

Answer:

2.89\ \text{s}

0.11 seconds

37.4\ \text{m}

Step-by-step explanation:

t_1 = Time taken by the pebble to hit the water

t_2 = Time taken by the sound to travel to the observer

t_1+t_2 = Time taken by the observer to listen to the splash after stone is thrown = 3 s

t_1=3-t_2

a = g = Acceleration due to gravity = 9.81\ \text{m/s}^2

u_s = Speed of sound = 340 m/s

The distance traveled by the pebble

s=ut+\dfrac{1}{2}at_1^2\\\Rightarrow s=0+\dfrac{1}{2}\times9.81(3-t_2)^2\\\Rightarrow s=4.905(9+t_2^2-6t_2^2)

Distance traveled by the sound

s=u_st\\\Rightarrow s=340\times t_2

The distance traveled by the sound and the pebble is equal

4.905(9+t_2^2-6t_2)=340\times t_2\\\Rightarrow 9+t_2^2-6t_2=\dfrac{340}{4.905}t_2\\\Rightarrow 9+t_2^2-6t_2=69.32t_2\\\Rightarrow t_2^2-75.32t_2+9=0\\\Rightarrow t_2=\frac{-\left(-75.32\right)\pm \sqrt{\left(-75.32\right)^2-4\times \:1\times \:9}}{2\times \:1}\\\Rightarrow t_2=75.2,0.11

Since t_1+t_2=3 the value of t_2 cannot be greater than 3.

So, time taken by the sound to reach the observer is 0.11 seconds.

Time taken by the pebble to hit the water is t_1=3-t_2=3-0.11=2.89\ \text{s}

Depth of the well is s=340t_2=340\times 0.11=37.4\ \text{m}

8 0
3 years ago
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