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Sedbober [7]
3 years ago
14

This equation is balanced: N2+3H2 - 2NH3 OA. True • B. False​

Chemistry
1 answer:
katen-ka-za [31]3 years ago
4 0

Answer:

True

Explanation:

N2 + 3h2 - 2NH3 is indeed a balanced equation therefore it is a "true statement" or option A. You can tell this equation is balanced because it has the same number of Nitrogen, and Hydrogen atoms on the same side keeping the equation balanced.

Hope this helps.

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What happens when magnesium reacts with dilute acid?
iogann1982 [59]

The magnesium dissolves to form magnesium chloride and hydrogen gas is released.

Mg  + 2HCl    -----> MgCl2  + H2(g).

5 0
3 years ago
What will knowledge of chemistry enable you to do?
mixer [17]
Be a chemist. Lol. Lessen waste, make chemicals more efficient, cure diseases... and stuff :)
4 0
3 years ago
A certain liquid X has a normal boiling point of 133.60°C and a boiling point elevation constant Kb= 2.46°C kg mol^-1.Calculate
Afina-wow [57]

Answer:

136.63 °C

Explanation:

ΔTb=Tb solution - Tb pure

Where; Tb pure = 133.60°C

molar mass of solute = 121.14 g/mol

number of moles of solute; 52.2g/121.14 g/mol = 0.431 moles

molality = 0.431 moles/350 * 10^-3 = 1.23 molal

Then;

ΔTb = Kb * m * i

Kb = 2.46°C kg mol^-1

m = 1.23 molal

i = 1

ΔTb = 2.46 * 1.23 * 1

ΔTb = 3.03 °C

Hence;

Tb solution = ΔTb + Tb pure

Tb solution = 3.03 °C + 133.60°C

Tb solution = 136.63 °C

6 0
3 years ago
Calculate the mass in grams of each sample.<br> 4.88x10^20 H2O2 molecules
AleksAgata [21]

4.88x10^20 H2O2 molecules

5 0
4 years ago
A 2.5 L container holds a sample of hydrogen gas at 291 K and 180 kPa.
netineya [11]

Answer:

The new temperature will be 565.83 K.

Explanation:

Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.

In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:

\frac{P}{T} =k

When an ideal gas goes from a state 1 to a state 2, it is true:

\frac{P1}{T1} =\frac{P2}{T2}

In this case:

  • P1= 180 kPa
  • T1= 291 K
  • P2= 350 kPa
  • T2= ?

Replacing:

\frac{180 kPa}{291 K} =\frac{350 kPa}{T2}

Solving:

T2=350 kPa*\frac{291 K}{180 kPa}

T2= 565.83 K

<u><em>The new temperature will be 565.83 K.</em></u>

6 0
3 years ago
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