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kvv77 [185]
3 years ago
15

Carbon dioxide and water react to form bicarbonate ion and hydronium ion. Hyperventilation (rapid breathing) causes more carbon

dioxide to be exhaled than normal. How will hyperventilation affect the pH of blood? Explain.
Chemistry
1 answer:
Pani-rosa [81]3 years ago
5 0

Answer:When a person hyperventilates they exhale more carbon dioxide than normal. As a result the carbon dioxide concentration in the blood is reduced and the bicarbonate/carbonic acid equilibrium shifts to the left. The corresponding drop in H3O+ concentration causes an increase in pH.

Explanation:

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german

Because things that are burnt have been changed into something else like moldy bread thats cooked.

It is chemical change because you cannot unburn something.

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3 years ago
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What is the main source of energy in a clear water stream in an open area
solniwko [45]

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c.sunlight

Explanation:

4 0
3 years ago
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As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.71 atm and a temperature of 25.0 C,
Semenov [28]

Answer:

1.32\times 10^{-3} mol/Lis the solubility of nitrogen gas in a diver's blood.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{N_2}=K_H\times p_{liquid}

where,

K_H = Henry's constant = 6.26 \times 10^{-4}mol/L.atm

p_{N_2} = partial pressure of nitrogen

p_{N_2}= P\times \chi_{N_2} (Raoult's law)

=2.71 atm\times 0.78=2.1138 atm

C_{N_2}=6.26 \times 10^{-4}mol/L.atm\times 2.1138 atm

C_{N_2}=1.32\times 10^{-3} mol/L

1.32\times 10^{-3} mol/Lis the solubility of nitrogen gas in a diver's blood.

3 0
3 years ago
I cant remember my mass, grams, and volume. and how to divide density
Bas_tet [7]
Mass divide by volume

M
__
V
7 0
3 years ago
PLEASE HELP!!!!!!
pogonyaev

Answer:

m_{B}^{theoretical}=0.365gB

Y=87.1\%

Explanation:

Hello there!

In this case, since the reaction (A->B) have an initial amount of pure 4-aminobenzoic acid, the first step to compute the theoretical yield is to solve the following stoichiometric setup:

m_{B}^{theoretical}=0.303gA*\frac{1molA}{137.14gA}*\frac{1molB}{1molA}*\frac{165.19 gB}{1molB}\\\\   m_{B}^{theoretical}=0.365gB

Whereas A stands for 4-aminobenzoic acid and B for the benzocaine. Moreover, we compute the percent yield by dividing the actual yield (0.318 g) by the theoretical one (0.365 g):

Y=\frac{0.318g}{0.365g} *100\%\\\\Y=87.1\%

Best regards!

4 0
2 years ago
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