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gtnhenbr [62]
3 years ago
14

3.25 is what percent of 125?

Mathematics
2 answers:
melomori [17]3 years ago
7 0

Answer:

4.0625

Step-by-step explanation:

fredd [130]3 years ago
3 0

Answer:

2.6

Step-by-step explanation:

p = x * 100 / y

and x = 3.25

and y = 125

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I'm stuck, please help me​
Sav [38]
60/48
x100
60/48=1.25
1.25x100
125%
3 0
3 years ago
Read 2 more answers
What is the best estimate for the answer to 321.786 + 240.273?
zvonat [6]
Round
321.786 is about 322
240.23 is about 240
322+240=562
about 562
3 0
3 years ago
Simplify, state all restrictions.
Kipish [7]

The simplified expression is \frac{1 - x - y}{x + y}and the restriction is y \ne -x

<h3>How to simplify the expression?</h3>

The expression is given as:

\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

\frac{x - y}{(2x - y)(2x - 3y)} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1

Rewrite the expression as products

\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1

Cancel out the common factors

\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1

Express 4x^2 - y^2 as (2x - y)(2x + y)

\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{(2x - y)(2x + y)}{(x + y)} -1

Cancel out the common factors

\frac{1}{x + y} -1

Take the LCM

\frac{1 - x - y}{x + y}

Hence, the simplified expression is \frac{1 - x - y}{x + y}and the restriction is y \ne -x

Read more about expressions at:

brainly.com/question/723406

#SPJ1

7 0
2 years ago
A package of 6 pairs of insulated gloves costs ​$51.54. What is the unit price of the pairs of gloves ​?
mafiozo [28]

Answer:

$8.59

Step-by-step explanation:

The unit price is just asking for what one pair of gloves cost.

\$ 51.54 \div6=\$8.59

∴The unit price of the pairs of gloves is $8.59

Hope this helps!

6 0
2 years ago
Read 2 more answers
NEED HELP HERE ASAP<br><br> 6. Find the cube roots of 27(cos 330° + i sin 330°).
VLD [36.1K]
<span>we have that

the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

 cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
7 0
3 years ago
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