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poizon [28]
2 years ago
15

The process by which a cell takes in a large particle is called

Chemistry
2 answers:
Ganezh [65]2 years ago
4 0

Answer:

endocytosis

Explanation:

yawa3891 [41]2 years ago
4 0

Answer:

A endocytosis

Explanation:

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B5%7D%20%2B%20%20%5Cfrac%7B2%7D%7B5%7D%20" id="TexFormula1" title=" \frac{1
Travka [436]
3/4 cause its addition
8 0
2 years ago
Convert 15.2 moles of K to atoms of K.
choli [55]

Answer:

\boxed {\boxed {\sf 9.15*10^{24} \ atoms \ K}}

Explanation:

To convert atoms to moles, Avogadro's Number must be used: 6.022*10²³.

This tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case it is the atoms of potassium. We can create a ratio.

\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }

Multiply by the given number of moles: 15.2

15.2 \ mol \ K *\frac {6.022*10^{23} \ atoms \ K }{ 1 \ mol \ K }

The moles of potassium cancel.

15.2 *\frac {6.022*10^{23} \ atoms \ K }{ 1 }

The denominator of 1 can be ignored.

15.2 * {6.022*10^{23} \ atoms \ K }{

Multiply.

9.15344*10^{24} \ atoms \ K

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated that is the hundredth place. The 3 in the thousandth place tells us to leave 5.

9.15*10^{24} \ atoms \ K

In 15.2 moles of potassium, there are <u>9.15*10²⁴ atoms of potassium.</u>

3 0
2 years ago
How has thermal energy, heat, and temperature change?
maria [59]

thermal energy leads to an increase in the kinetic energy also increasing in temperature hope this helped!

3 0
3 years ago
Read 2 more answers
What are the types of Asexual reproduction? <br><br> need this asap bro uyftghjkddfs
kolezko [41]

Answer:

The types of Asexual reproduction include:  fission, fragmentation, budding, vegetative reproduction, spore formation and agamogenesis.

5 0
2 years ago
What volume is needed to store 0.80 moles of helium gas at 204.6 kpa and 300 k?
shepuryov [24]
Answer is: 9,7 L is needed to store helium gas.
n(He) = 0,80 mol.
p(He) = 204,6 kPa.
T = 300 K.
R = 8,314 J/K·mol; universal gas constant.
Use ideal law eqaution: p·V = n·R·T.
V = n·R·T / p.
V(He) = 0,80 mol · 8,314 J/K·mol · 300 K ÷ 204,6 kPa.
V(He) = 9,75 L.


3 0
2 years ago
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