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Semenov [28]
3 years ago
7

An atom of barium has the atomic symbol shown below. Which statement is FALSE regarding this atom of barium?

Chemistry
2 answers:
Sergio [31]3 years ago
5 0

Answer:

C. The atomic number of this atom is 138

Explanation:

levacccp [35]3 years ago
5 0

Answer:

C

Explanation:

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<span>Uranium-236 is intermediate nuclei. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-bomb.

Following is the reaction involved in above process:

</span>^{235}U+ ^{1}n →  ^{236}U→ ^{144}Ba + ^{89}Kr + 3 ^{1}n<span> + 177 MeV
</span>
Here, 
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^{1}n = projectile,
^{236}U = intermediate nuclei,
^{144}Ba and ^{89}Kr = Fission product



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Which statement goes against the kinetic theory of gases?
AURORKA [14]

the answer is c. Gas molecules will never collide with the walls of the container

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Pentane is a small liquid hydrocarbon, between propane and gasoline in size at C5H12. The density of pentane is 0.626 g/mL and i
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Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and 3.073\times 10^4kJ/L respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

\Delta H^o_{comb}=-3535kJ/mol

Fuel value = \frac{\Delta H^o_{comb}}{\text{Molar mass of pentane}}

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Fuel value = \frac{3535kJ/mol}{72g/mol}

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Now we have to calculate the fuel density of pentane.

Fuel density = Fuel value × Density

Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL = 3.073\times 10^4kJ/L

Thus, the fuel density of pentane is 3.073\times 10^4kJ/L

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