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sdas [7]
3 years ago
15

What is the neutral atom that has its first two energy levels filled, has 7 electrons in its third energy level, and has no othe

r electrons
Chemistry
1 answer:
nikitadnepr [17]3 years ago
3 0
Idk sorry sorry so so so so so so so so sorry
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Using the activity series, write balanced chemical equations for the following reactions. If not reaction occurs, simply write N
MissTica

Answer:

a) 2 Ni (s) + Cu(NO_3)_2 (aq) \longrightarrow Cu(s) + 2 NiNO_3 (aq)

b) NR

c) NR

d) 2 Cr (s) + 3 CoCl_2 (aq) \longrightarrow 3 Co(s) + 2CrCl_3 (aq)

e) NR

Explanation:

a) Nickel is more reactive than copper so the first one will displace the other:

2 Ni (s) + Cu(NO_3)_2 (aq) \longrightarrow Cu(s) + 2 NiNO_3 (aq)

b) Due to the higher reactivity the magnesium has compared to the zinc, the first will remain in solution and the second will reamin solid. So, NR.

c) No reaction occurs, gold is resistant to acid in normal conditions due to its characteristic as noble metal.

d) Chromium is more reactive than cobalt so the last one will be displaced:

2 Cr (s) + 3 CoCl_2 (aq) \longrightarrow 3 Co(s) + 2CrCl_3 (aq)

e) Nothing happens, the reduction potencial of the hydrogen gas bubbled ins't enough to reduce the silver.

8 0
3 years ago
How does a sample of hydrogen at 10 °C compare to a sample of hydrogen at 350 K?
Andrej [43]

Answer: -

C. The hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.

Explanation: -

The kinetic energy of gas molecules increase with the increase in the temperature of the gas. With the increase in kinetic energy, the gas molecules also move faster. Thus with the increase of temperature, the speed of the molecules increase.

Temperature of first hydrogen gas sample is 10 °C.

10 °C means 273+10 = 283 K

Thus first sample temperature = 283 K

The second sample temperature of the hydrogen gas  is 350 K.

Thus the temperature is increased.

So both the kinetic energy and speed of molecules is more for the hydrogen gas sample at 350 K.

Thus the hydrogen at 10 °C has slower-moving molecules than the sample at 350 K.

Hence the answer is C.

7 0
4 years ago
Read 2 more answers
A particular solution of NaOH has hydronium concentration of 4x10-9 M. what is the solution’s pH?
bearhunter [10]

Answer:

The pH of the solution is 8, 40-

Explanation:

The pH indicates the acidity or basicity of a substance. PH values between 0 and less than 7 indicate acidic solutions, 7 neutral and greater than 7 to 14 basic. It is calculated as

pH = -log (H30+)

pH= -log (4x10-9M)

<em>pH=8,40</em>

8 0
3 years ago
One cubic millimeter (mm3) of blood contains 7.0 x 106 red blood cells. How many red blood cells are in 1.0 L of blood?
just olya [345]
The question gives us a conversion factor---> 1 mm3= 7.0 x 10^6 RBC. so, to find how many red blood cells we have, we first need to convert the Liters to cm3 using this conversion factor--> 1 mL= 1 cm3

i have attached how to solve this problem.


7 0
3 years ago
The wall of an industrial furnace is constructed from 0.15-m-thick, fireclay brick having a thermal conductivity of LZ W/m.K. Me
aliya0001 [1]

Answer:

The rate of heat loss through the wall is 1700 watts.

Explanation:

The complete statement of the problem is:

<em>The wall of an industrial furnace is constructed from 0.15-m-thick, fireclay brick having a thermal conductivity of 1.7 W/m·K. Measurements made during steady state operation reveal temperatures of 1400 and 1150 K at the inner and outer sur- faces, respectively. What is the rate of heat loss through a wall that is 0.5 m by 1.2 m on a side?</em>

Given that wall of the industrial furnace is under steady conditions of heat transfer and whose configuration is a flat element, we use the equation of conductive heat transfer rate (\dot Q), measured in watts:

\dot Q = \frac{k\cdot w\cdot h}{l}\cdot (T_{i}-T_{o})

Where:

k - Thermal conductivity, measured in watts per meter-Kelvin.

w - Width of the wall, measured in meters.

h - Height of the wall, measured in meters.

l - Thickness of the wall, measured in meters.

T_{i} - Inner surface temperature, measured in Kelvin.

T_{o} - Outer surface temperature, measured in Kelvin.

If we know that k = 1.7 \,\frac{W}{m\cdot K}, w = 1.2\,m, h = 0.5\,m, l = 0.15\,m, T_{i} = 1400\,K and T_{o} = 1150\,K, the steady state heat transfer is:

\dot Q = \left[\frac{\left(1.7\,\frac{W}{m\cdot K} \right)\cdot (1.2\,m)\cdot (0.5\,m)}{0.15\,m} \right]\cdot (1400\,K-1150\,K)

\dot Q = 1700\,W

The rate of heat loss through the wall is 1700 watts.

3 0
3 years ago
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