Answer:
0.3192 M
Explanation:
From the question given above, the following data were obtained:
Volume of stock solution (V1) = 5.32 mL Molarity of stock solution (M1) = 6 M
Volume of diluted solution (V2) = 100 mL
Molarity of diluted solution (M2) =?
We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:
M1V1 = M2V2
6 × 5.32 = M2 ×100
31.92 = M2 × 100
Divide both side by 100
M2 = 31.92 / 100
M2 = 0.3192 M
Therefore, the molarity of the diluted solution is 0.3192 M.
A study assessing the effect of anxiety (low vs. high) and stress (low vs. moderate vs. high) on test.
Everyone experiences anxiety occasionally, but persistent anxiety can reduce your quality of life. Though likely best known for altering behavior, worry can have negative effects on our physical health. Anxiety speeds up our heartbeat and breathing, concentrating blood flow to the parts of our brains that need it. You are getting ready for a challenging situation by having this extremely bodily reaction. Test performance may be impacted by anxiety. According to studies, pupils with low levels of test anxiety perform better on multiple-choice question (MCQ) exams than pupils with high levels of anxiety. Studies have indicated that female students have greater levels of test anxiety than male students.
Learn more about anxiety here:
brainly.com/question/4913240
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Answer:
160.32 grams of Ca or 160 if rounded
Explanation:
Multiply moles of Ca by the conversion factor (molar mass of calcium) 40.08 g Ca/ 1 mol Ca, which then allows the cancelation of moles, leaving grams of Ca.
4 mol*40.08g/mol = 160.32 grams of Ca
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We can express the rate equation in this form:
-r = k A^n B^m
where -r is the rate
k is the rate constant,
A is the concentration of CH3Cl
n is the order with respect to CH3Cl
B is the concentration of H2O
m is the order with respect to H2O
We can solve this by trial and error or by calculus. The first method is easier. The rate constant does not depend on the concentration of the reactant. Assume values of n and m and solve for k in each experiment. The only option that gives really close values of k in each experiment is:
<span>C. CH3Cl: firstorder H2O: second order
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