Very simple, in the lab, you can determine the mass of water by simply weight it in a balance.
Answer:
Na₂SO₄
Explanation:
Barium nitrate, Ba(NO₃)₂ produce precipitate with SO₄²⁻, CO₃²⁻. That means the precipitate could be obtained from Na₂SO₄ and Na₂CO₃.
Also, magnesium nitrate, Mg(NO₃)₂, produce precipitate just with CO₃²⁻. As the unknown solution produce no precipitate, the unknown compound is:
<em>Na₂SO₄</em>
We may not see notice it but plate tectonics actually have a "recycle" process. However, scientist reported that it happens in a span of 500 million years. Over the years, the oceanic crusts are pressured to the topmost layer of the mantle causing the oceanic crusts to melt and mix with the Earth's mantle. Such crust blending results to the formation of volcanoes underwater. In time, the said volcanoes would erupt causing the formation of new oceanic and continental crusts.
The noble gases are helium, neon, argon, krypton, xenon, radon, and ununoctium. The noble gases are relatively nonreactive. This is because they have a completevalence shell<span>. They have little tendency to </span>gain<span> or lose </span>electrons. <span>These gases all have similar properties under standard conditions: they are all odorless, colorless, monatomic gases with very low chemical </span>reactivity<span>. The six noble gases that occur naturally are helium (He), Neon (Ne), Argon (Ar), Krypton (Kr), Xenon (Xe), and Radon (Rn).</span>
Answer:
The volume of the air is 0.662 L
Explanation:
Charles's Law is a gas law that relates the volume and temperature of a certain amount of gas at constant pressure. This law says that for a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement they have. the gas molecules. This is represented by the quotient that exists between volume and temperature will always have the same value:
If you have a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment and several the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:
In this case:
- V1= 0.730 L
- T1= 28 °C= 301 °K (0°C= 273°K)
- V2= ?
- T2= 0°C= 273 °K
Replacing:
Solving:
V2=0.662 L
<u><em>The volume of the air is 0.662 L</em></u>
