Answer:
d
Explanation:
when one variables is zero ,the other is also zero
Answer:
Avogadro's law.
Explanation:
Avogadro’s law states that, equal volumes of all gases at the same temperature and pressure contain the same number of molecules.
Mathematically,
V n
V = Kn where V = volume in cm3, dm3, ml or L; n = number of moles of gas;
K = mathematical constant.
The ideal gas equation is a combination of Boyle's law, Charles' law and Avogadro’s law.
V 1/P at constant temperature (Boyle’s law)
V T at constant pressure ( Charles’law)
V n at constant temperature and pressure ( Avogadro’s law )
Combining the equations yields,
V nT/P
Introducing a constant,
V = nRT/P
PV = nRT
Where P = pressure in atm, Pa, torr, mmHg or Nm-2; V = volume in cm3, dm3, ml or L; T = temperature in Kelvin; n = number of moles of gas in mol; R = molar gas constant = 0.082 dm3atmK-1mol-1
Answer:

Explanation:
So suppose the axis of rotation is perpendicular to the surface of the disk, then the moment of inertia can be calculated as the following:

We can convert the rotation speed in term of 0.8 seconds per revolution to the angular velocity knowing that each revolution is 2π

Then the rotational angular momentum of the disk is:

In case the axis of rotation is parallel with the surface, the moment of inertia would have a formula of:

The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.
<h3>What is force?</h3>
Force is defined as the product of mass and acceleration of an object.
Friction is defined as the force that resists the movement of an object over another.
Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.
Learn more about force here:
brainly.com/question/12970081
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Answer:
La potencia de la bombilla es de 1056 W.
Explanation:
La potencia de la bombilla se puede calcular usando la siguiente ecuación:

En donde:
P: es la potencia
I: es la corriente = 2,4 A
V: es la diferencia de potencial = 440 V
Entonces, la potencia es:

Por lo tanto, la potencia de la bombilla es de 1056 W.
Espero que te sea de utilidad!