The formula for acceleration due to gravity can be
calculated using the formula:
g= G m / r^2
where g is gravity, G is gravitational constant, m is
mass, r is radius
So we can see that if we increase m by 4, so g also
increase by 4. But if the radius is decreased to ¼, therefore the gravity will be
divided by (1/4)^2. So:
4 / (1/4)^2 = 64
So the gravity on the surface will be:
64 g
<span>(64 times that of Earth’s gravity)</span>
Answer:
The Gauge pressure at 9 meters depth is ![150 \, kPa](https://tex.z-dn.net/?f=150%20%5C%2C%20kPa)
Explanation:
Gauge pressure is the difference between absolute pressure and some reference pressure, most commonly atmospheric pressure. The increment in pressure caused by a static fluid is given by:
where
is the density of the liquid, g is the accleration due to gravity and d is the depth.
Now, we see that
is linearly proportional to d, and we can assume that
remains constant, because liquids are usually not compressible.
Given that the greater depth is simply 3 times the smaller depth:
![d_2=3\cdot d_1\\9\,m= 3 \cdot 3\,m](https://tex.z-dn.net/?f=d_2%3D3%5Ccdot%20d_1%5C%5C9%5C%2Cm%3D%203%20%5Ccdot%203%5C%2Cm)
at
of depth will also be three times the gauge pressure at
of depth.
We could also have calculated
ny using:
![\Delta P = \rho \,g \,d\\\\\rho = \frac{\Delta P}{g \, d}\\\\\rho = \frac{\Delta P}{g \, d}= \frac{30 \,kPa}{9.8 \frac{m}{s^2} \, 3\,m}=1020.41 \frac{kg}{m^3}](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20%5Crho%20%5C%2Cg%20%5C%2Cd%5C%5C%5C%5C%5Crho%20%3D%20%5Cfrac%7B%5CDelta%20P%7D%7Bg%20%5C%2C%20d%7D%5C%5C%5C%5C%5Crho%20%3D%20%5Cfrac%7B%5CDelta%20P%7D%7Bg%20%5C%2C%20d%7D%3D%20%5Cfrac%7B30%20%5C%2CkPa%7D%7B9.8%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%20%20%5C%2C%203%5C%2Cm%7D%3D1020.41%20%5Cfrac%7Bkg%7D%7Bm%5E3%7D)
and used this result to calculate the gauge pressure. These are both similar methods that yield the same result
Answer:
1.14*10^-3m
Explanation:
We know that
Volume= mass/ density
But
Area x depth= mass/density
πr²*depth= mass/density
r²=m/πdp
So
r= √0.35/3.142*0.085*1000
r= 1.14*10^-3m
<span>F= ma so... a=F/m=
8N÷2kg=4m/s/s
THEN
vf²=vi²+2ad
vf²=0²+(2)(4)(18) = 144
vf²=√144
vf=12
THEN
KE = 1/2mv²
KE= (.5)(2)(12²)
KE = 144</span>
Answer:
The Sun is the center of our solar system and makes up 99.8 percent of the mass of the entire solar system.
Explanatio