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sesenic [268]
3 years ago
7

A bowl contains 28 black,21 red,23 blue,and 10 green balls.A ball is drawn at random. P(blue)

Mathematics
2 answers:
Lera25 [3.4K]3 years ago
8 0
To find the probability of picking a blue marble, first we add all the marbles together:
28+21+23+10=82

since there are 23 blue marbles in the bag out of a total of 82 marbles, the probability of picking a blue marble is 23/82.

P(blue)= 23/82

hope this helps
Pachacha [2.7K]3 years ago
4 0

P(blue) is 23/82 the sum is 82 and there is 23 blue balls

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Answer:

P(Green\ and\ Green) = \frac{25}{144}

Step-by-step explanation:

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Required

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P(Green\ and\ Green) = P(Green) * P(Green)

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