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Oksi-84 [34.3K]
4 years ago
10

A bicyclist goes from a speed of 5 m/s to a speed of 10 m/s. What happens to her kinetic energy?

Physics
1 answer:
serg [7]4 years ago
4 0

Answer:

C

Explanation:

The kinetic energy of an object can be calculated via the following equation:

k =  \frac{1}{2} m {u}^{2}

where:

K : kinetic energy

m: mass of the object

v: its velocity

when the speed changes, the kinetic energy changes as well. Lets suppose that it doubles, as on the problem stated. Then K is increased by a factor of four. in other words...

newk =  \frac{1}{2} m {(newu)}^{2}  =  \frac{1}{2} m {(2u)}^{2}   \\  =  \frac{1}{2} m(4 {u}^{2} ) = 4( \frac{1}{2} m {u}^{2} ) = 4k

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