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Fofino [41]
3 years ago
6

A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator

? b. How much work does the tension in the elevator cable do on the elevator? c. What is the elevator’s kinetic energy after traveling 10 m?

Physics
1 answer:
Ivenika [448]3 years ago
5 0
Here you go mate. Hope it helps u. Pls follow me in reddit lol username: RobloxNoob2006

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Answer:

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Explanation:

L = 100 m

A = 1 mm^2 = 1 x 10^-6 m^2

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Let the cable stretch be ΔL.

By the formula of Young's modulus

Y=\frac{F\times L}{A\times\Delta L}

\Delta L=\frac{F\times L}{A\times\Y}

\Delta L=\frac{1000\times 100}{10^{-6}\times10^{11}}

ΔL = 1 m

Thus, the cable stretches by 1 m.

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