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Fofino [41]
3 years ago
6

A 1000 kg elevator accelerates upward at 1.0 m/s2 for 10 m, starting from rest. a. How much work does gravity do on the elevator

? b. How much work does the tension in the elevator cable do on the elevator? c. What is the elevator’s kinetic energy after traveling 10 m?

Physics
1 answer:
Ivenika [448]3 years ago
5 0
Here you go mate. Hope it helps u. Pls follow me in reddit lol username: RobloxNoob2006

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A hockey stick of mass ms and length L is at rest on the ice (which is assumed to be frictionless). A puck with mass mp hits the
krek1111 [17]

Answer:

L = mp*v₀*(ms*D) / (ms + mp)

Explanation:

Given info

ms = mass of the hockey stick

uis = 0 (initial speed of the hockey stick before the collision)

xis = D (initial position of center of mass of the hockey stick before the collision)

mp = mass of the puck

uip = v₀ (initial speed of the puck before the collision)

xip = 0 (initial position of center of mass of the puck before the collision)

If we apply

Ycm = (ms*xis + mp*xip) / (ms + mp)

⇒  Ycm = (ms*D + mp*0) / (ms + mp)

⇒  Ycm = (ms*D) / (ms + mp)

Now, we can apply the equation

L = m*v*R

where m = mp

v = v₀

R = Ycm

then we have

L = mp*v₀*(ms*D) / (ms + mp)

5 0
3 years ago
Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a
cupoosta [38]

Answer:

2.2 s

Explanation:

Using the equation for the period of a physical pendulum, T = 2π√(I/mgh) where I = moment of inertia of leg about perpendicular axis at one point =  mL²/3 where m = mass of man = 67 kg and L = height of man = 1.83 m, g = acceleration due to gravity = 9.8 m/s² and h = distance of leg from center of gravity of man = L/2 (center of gravity of a cylinder)

So, T = 2π√(I/mgh)

T = 2π√(mL²/3 /mgL/2)

T = 2π√(2L/3g)

substituting the values of the variables into the equation, we have

T = 2π√(2L/3g)

T = 2π√(2 × 1.83 m/(3 × 9.8 m/s² ))

T = 2π√(3.66 m/(29.4 m/s² ))

T = 2π√(0.1245 s² ))

T = 2π(0.353 s)

T = 2.22 s

T ≅ 2.2 s

So, the period of the man's leg is 2.2 s

7 0
3 years ago
What is the relationship between Newton's second law and gravitational acceleration?
beks73 [17]

Answer:

Correct answer:  Fg = m · g

Explanation:

Newton's second law states that if a resultant force is applied to an object, the object begins to move at an accelerated rate.

The formula that presents this is:

F = m · a  

this formula applies to an object moving on some surface

where m is the mass of the object and a the acceleration of the object

Let's take it now and watch the free fall:

The formula that presents this is:

Fg = m · g  

this formula applies to an object moving at free fall in vertical direction

Free fall is also an accelerated movement to which Newton's second law applies.

where m is the mass of the object and g the gravitation acceleration of the object . We also know that g is equal:

g = γ · Me / d² where Me is mass of the earth

God is with you!!!

5 0
3 years ago
Plz i need help fast im timed!!!!!!
professor190 [17]

Answer:

sorry i throght i had the answer

Explanation:

4 0
2 years ago
Read 2 more answers
What happens when the mass of an object is greter
Paul [167]
The acceleration goes up.
4 0
3 years ago
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