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tatuchka [14]
2 years ago
5

I need help with this

Mathematics
1 answer:
Anna11 [10]2 years ago
5 0

Answer:

look at the picture i sent.......

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PLEASE HELP I DONT UNDERSTAND ILL GIVE MORE IF ITS RIGHT
erastova [34]

Answer:

17ft

Step-by-step explanation:

What you're going to do is solve this backwards so to find volume the eqation is v=(pir^2)h, so what you're going to do is:

833pi=(pi7^2)h                 you cross out pi and square 7                           833=49*h                         then you divide 49 from both sides and get 17

8 0
3 years ago
I NEED HELP ASAP I WILL MARK YOU THE BRAINLIEST
Nataliya [291]
Alternate Interior Angles. You’re welcome
7 0
2 years ago
100 POINTS PLEASE HELP ME I BEG 100 POINTS
Marrrta [24]

Answer:

see explanation

Step-by-step explanation:

(1)

Since FE = FG the triangle is isosceles with ∠ E = ∠ G, then

∠ E = \frac{180-106}{2} = \frac{74}{2} = 37°

(2)

Since all 3 sides are congruent then triangle is equilateral with the 3 angles being congruent, 60° each , then

12y = 60 ( divide both sides by 12 )

y = 5

(3)

The 3 angles are congruent then triangle is equilateral with the 3 sides being congruent, then

KL = JL , that is

4t - 8 = 2t + 1 ( subtract 2t from both sides )

2t - 8 = 1 ( add 8 to both sides )

2t = 9 ( divide both sides by 2 )

t = 4.5

(4)

Given ∠ B = ∠ C then triangle is isosceles with 2 legs being congruent , that is

AB = AC

4x + 1 = 9 ( subtract 1 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

Then

perimeter = AB + BC + AC = 4x + 1 + 2x + 3 + 9

                                            = 6x + 13

                                            = 6(2) + 13

                                            = 12 + 13

                                            = 25

7 0
2 years ago
Read 2 more answers
34 X 19/38 reduced to lowest term
torisob [31]

19/38 = 1/2 (divided top and bottom by 19)

so

34 X 19/38

= 34 X 1/2

= 34/2

= 17/1

Answer

17/1 (or 17)

7 0
2 years ago
How do you solve this?
k0ka [10]
x^2-3x-4=0\\\\x^2-2x\cdot\frac{3}{2}=4\ \ \ /+(\frac{3}{2})^2\\\\x^2-2x\cdot\frac{3}{2}+(\frac{3}{2})^2=4+(\frac{3}{2})^2\\\\(x-\frac{3}{2})^2=4+\frac{9}{4}\\\\(x-\frac{3}{2})^2=\frac{16}{4}+\frac{9}{4}\\\\(x-\frac{3}{2})^2=\frac{25}{4}\\\\x-\frac{3}{2}=\pm\sqrt\frac{25}{4}

x-\frac{3}{2}=\pm\frac{\sqrt{25}}{\sqrt4}\\\\x-\frac{3}{2}=\pm\frac{5}{2}\\\\x-\frac{3}{2}=-\frac{5}{2}\ or\ x-\frac{3}{2}=\frac{5}{2}\\\\x=-\frac{5}{2}+\frac{3}{2}\ or\ x=\frac{5}{2}+\frac{3}{2}\\\\x=-\frac{2}{2}\ or\ x=\frac{8}{2}\\\\x=-1\ or\ x=4
5 0
2 years ago
Read 2 more answers
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