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2 years ago

15

Select all the sequences of transformations that always maintain congruence. a reflection and then a translation a translation a

nd then a rotation a rotation and then a reflection a dilation and then a reflection a rotation and then a dilation a translation and then a dilation

1 answer:

oee [108]2 years ago

6 0

A reflection followed by translation, a translation followed by rotation, and a rotation followed by reflection all preserve congruence.

Anything that changes the size of the figure does not preserve congruence. The other three choices all have a dilation in them; a dilation changes the size of a figure. Therefore it does not preserve congruence.

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A lumber yard offers boards based on wood species, size, and grade. If a customer can choose among 3 species, 3 sizes, and 2 gra

frutty [35]

Answer:

18

Step-by-step explanation:

3 x 3 = 9

9 x 2 = 18

5 0

2 years ago

Right isosceles triangles are constructed on the sides of a 3−4−5 right triangle, as shown. A capital letter represents the area

Ivenika [448]

Answer:

1

Step-by-step explanation:

because the triangles are isosceles, that means that the area of Z is 5x5x1/2, which equals 12.5

the area of X is 4.5

the area of y is 8

(8+4.5)/(12.5) = 1

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2 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

28 students in the class 75% pass how many students pass

SashulF [63]

Answer:

21 students pass

Step-by-step explanation:

Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction $\frac{75}{100}$ (which is 75% represented as a fraction).

$\frac{X}{28} = \frac{75}{100}$

The fraction $\frac{75}{100}$ can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with $\frac{3}{4}$ .

$\frac{X}{28} = \frac{3}{4}$

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

$\frac{X}{28} * 28 * 4 = \frac{3}{4} * 4 * 28$

The denominators cancel out leaving you with a simple equation to simplify.

$4* X = 3 * 28$

$4X = 84$

Finally, divide both sides by four in order to isolate the variable.

$\frac{4X}{4} = \frac{84}{4}$

X = 21.

5 0

3 years ago

2+2= what +6 HA they cant repo this so u guys can get points

Rzqust [24]

Answer:

10

Step-by-step explanation:

2+2=4

4+6= 10

5 0

2 years ago

Read 2 more answers